Rev. 2.0, 11/00, page 497 of 1037
Thus the receive margin in asynchronous mode is given by equation (1) below.
M =
(0.5
−
1
)
−
(L
−
0.5) F
−
D
−
0.5
(1+F)
×
100%
2N
N
…..(1)
Where M: Receive margin (%)
N: Ratio of bit rate to clock (N = 16)
D: Clock duty (D = 0 to 1.0)
L: Frame length (L = 9 to 12)
F: Absolute value of clock rate deviation
Assuming values of F = 0 and D = 0.5 in equation (1), a receive margin of 46.875% is given by
equation (2) below.
When D = 0.5 and F = 0,
M =(0.5
−
1
)
×
100%
2
×
16
=46.875%
…..(2)
However, this is only a theoretical value, and a margin of 20% to 30% should be allowed in
system design.
Summary of Contents for Hitachi H8S/2191
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