Siemens siprotec 7SA6, Manual

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Technical Data
10-38
7SA6 Manual
C53000-G1176-C156
10.16 Fault Location
Start with trip command or drop-off
Setting range reactance (secondary) 0.005
Ω
/km to 6.500
Ω
/km
2
)
(steps 0.001
Ω
/km) or
0.005
Ω
/mile to 10.000
Ω
/mile
2
)
(steps 0.001
Ω
/mile)
Parallel line compensation can be switched on/off
Set values are the same as for distance
protection (see Section 10.2)
Load current compensation correction of the X-value
for single-phase earth faults can be switched on/off
Output of the fault distance in
Ω
primary and
Ω
secondary,
in km or miles line
1
),
in % of the line length
1
)
Measuring tolerances 2.5 % of line length
with sinusoidal measured quantities at 30°
≤ ϕ
k
≤
90° and U
k
/U
N
≥
0.1
Further output options as analog value 0 mA to 22.5 mA;
(dependent on order variant) as BCD–code 4 bit units + 4 bit tens +
1 bit hu 1 validity bit
output time, settable 0.01 s to 30.00 s;
∞
(steps 0.01 s)
1
) Output of the fault distance in km, miles, and % requires homogeneous lines.
2
) Secondary values based on I
N
= 1 A; for I
N
= 5 A the impedances are to be divided by 5.
10.17 Circuit Breaker Failure Protection (optional)
Circuit Breaker
Monitoring Current flow monitoring 0.05 A to 20.00 A
1
)
(steps 0.01 A)
Drop-off to pick-up ratio approx. 0.95
Tolerance 5 % of the set value or 0.01 A
1
)
Monitoring of circuit-breaker
auxiliary contact position
- for three-pole tripping
binary input for circuit breaker
auxiliary contact
- for single-pole tripping 1 binary input for auxiliary contact per pole
or
1 binary input for series connection NO
contact and NC contact
Note: The circuit breaker failure protection can also operate without the indicated circuit breaker auxiliary contacts, but the
function range is then reduced. Auxiliary contacts are necessary for the circuit breaker failure protection for tripping without
or with a very low current flow (e.g. Buchholz protection), stub fault protection, circuit breaker pole discrepancy monitoring.
1
) Secondary values based on I
N
= 1 A; for I
N
= 5 A the currrent values are to be
multiplied by 5.