12-21-2
Chapter 12
Inverter Function
12.21.2
Outputting a signal when the
frequency reaches the target
• I want to detect that the output frequency to the
motor has become a frequency larger than the set
value and make a notification to the system.
• Assign the output terminal functions 003 [FA2] and
005 [FA4] exceeding set frequency signal to one of
[CC-01] to [CC-07] that corresponds to the output
terminal and output the signals.
• The signals [FA2] and [FA4] can be output to output
terminal functions individually as the exceeding set
frequency output signal.
• The signals [FA2] and [FA4] will be output when the
enabled output frequency exceeds the setting.
• Operation example
Parameter
• The operation of [FA2] can be set through [CE-10]
and [CE-11].
• The operation of [FA4] can be set through [CE-12]
and [CE-13].
Item
Parameter
Data
Description
Output terminal
function selection
[CC-01]~[CC-05]
003
005
003 [FA2]: The exceeding set frequency
signal will be output to the output terminal
assigned.
005 [FA4]: The exceeding set frequency
signal 2 will be output to the output
terminal assigned.
Relay output
terminal function
selection
[CC-06]
Relay output
terminal function
selection
[CC-07]
Acceleration
reaching frequency
1
[CE-10]
0.00~590.00(Hz)
The frequency to judge that the frequency
has been reached in acceleration and
output the signal [FA2].
Deceleration
reaching frequency
1
[CE-11]
0.00~590.00(Hz)
The frequency to judge that the frequency
has been reached in deceleration and
output the signal [FA2].
Acceleration
reaching frequency
2
[CE-12]
0.00~590.00(Hz)
The frequency to judge that the frequency
has been reached in acceleration and
output the signal [FA4].
Deceleration
reaching frequency
2
[CE-13]
0.00~590.00(Hz)
The frequency to judge that the frequency
has been reached in deceleration and
output the signal [FA4].
Q
A
!
fon: 1% of the maximum
frequency
foff: 2% of the maximum
frequency
[CE-10]
[CE-11]
fon
foff
Output
Frequency
[FA2]
foff
fon
[CE-12]
[CE-13]
[FA4]
(Operation example)
Maximum frequency: 60 Hz
When [CE-10] = [CE-11] = 50 Hz
• fon=60×0.01=0.6Hz
• foff=60×0.02=1.2Hz
• In acceleration: On at 50 - 0.6 = 49.4
Hz
• In deceleration: On at 50 - 1.2 = 48.8
Hz
ON
OFF
ON
OFF
Summary of Contents for SJ Series
Page 39: ...5 4 Chapter 5 Included Items Memo ...
Page 55: ...6 16 Chapter 6 Installation Memo ...
Page 91: ...7 36 Chapter 7 Wire Connection and Optional Devices Memo ...
Page 135: ...9 40 Chapter 9 Operating Instructions Memo ...
Page 145: ...10 10 Chapter 10 Test Run Memo ...
Page 159: ...12 2 6 Chapter 12 Inverter Functions Memo ...
Page 169: ...12 3 10 Chapter 12 Inverter Functions Memo ...
Page 195: ...12 5 8 Chapter 12 Inverter Functions Memo ...
Page 217: ...12 8 12 Chapter 12 Inverter Function Memo ...
Page 287: ...12 10 32 Chapter 12 Inverter Functions Memo ...
Page 303: ...12 11 16 Chapter 12 Inverter Functions Memo ...
Page 349: ...12 15 8 Chapter 12 Inverter Function Memo ...
Page 395: ...12 17 34 Chapter 12 Inverter Functions Memo ...
Page 397: ...12 18 2 Chapter 12 Inverter Functions Memo ...
Page 415: ...12 19 18 Chapter 12 Inverter Function Memo ...
Page 581: ...15 10 Chapter 15 Optional Cassettes Memo ...
Page 591: ...16 10 Chapter 16 ProDriveNext EzSQ Memo ...
Page 642: ...18 49 Chapter 18 Tips FAQ Troubleshooting Memo ...
Page 650: ...19 8 Chapter 19 Maintenance and Inspection Memo ...
Page 781: ...Appendix 1 70 Appendix 1 List of Parameters Memo ...