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6.74
SEL-421 Relay
Instruction Manual
Date Code 20171021
Protection Applications Examples
345 kV Tapped Overhead Transmission Line Example
Calculate the transformer reactances.
Equation 6.43
Use these assumptions from
to create a simplified form of the
downstream parallel impedance.
Equation 6.44
The secondary base impedance is calculated as follows:
Equation 6.45
Calculate the parallel impedance in secondary ohms.
Equation 6.46
To determine whether the 32QG element always operates correctly during
reverse unbalanced faults, check the following condition:
Z2F < |Z
1L1
| + |Z
2P
|
2
< 2
+ 1.35
2
< 3.35
The condition is satisfied; the reverse negative-sequence voltage-polarized direc-
tional element decision is correct during reverse unbalanced faults.
X
H
0.5
X
HM
X
HL
X
ML
–
+
•
=
0.5
0.016 0.6 0.4
–
+
•
=
0.108 per-unit
=
X
M
0.5
X
HM
X
ML
X
HL
–
+
•
=
0.5
0.016 0.4 0.6
–
+
•
=
0.092
–
per-unit
=
X
L
0.5
X
HL
X
ML
X
HM
–
+
•
=
0.5
0.6 0.4 0.016
–
+
•
=
0.492 per-unit
=
Z
2P
j X
1L3
X
H
X
M
+
+
X
1L2
=
j
X
1L3
X
H
X
M
+
+
X
1L2
•
X
1L3
X
H
X
M
+
+
X
IL2
+
-------------------------------------------------------------------
=
j
0.038 0.108 0.092
–
+
0.025
•
0.038 0.108 0.092
–
+
0.025
+
-----------------------------------------------------------------------------
=
j0.017 per-unit primary
=
Z
base
CTR
345 kV
2
•
PTR 100 MVA
•
---------------------------------------------
=
200
345 kV
2
•
3000 100 MVA
•
--------------------------------------------
=
79.35
=
Z
2P
ondary
sec
Z
2P primary
Z
base
•
=
J0.017 79.35
•
=
1.35
secondary
=
Summary of Contents for SEL-421-4
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