Allen-Bradley Kinetix 5700, User Manual, Page: 37 / 376

Rockwell Automation Publication 2198-UM002E-EN-P - February 2018 37
Plan the Kinetix 5700 Drive System Installation Chapter 2
Enclosure Selection
This example is provided to assist you in sizing an enclosure for your
Kinetix 5700 drive system. You need heat dissipation data from all components
planned for your enclosure to calculate the enclosure size (refer to
Table 8 ).
With no active method of heat dissipation (such as fans or air conditioning)
either of the following approximate equations can be used.
If the maximum ambient rating of the Kinetix 5700 drive system is 50 °C
(122 °F) and if the maximum environmental temperature is 20 °C (68 °F), then
T=30. In this example, the total heat dissipation is 416 W (sum of all
components in enclosure). So, in the equation below, T=30 and Q=416.
In this example, the enclosure must have an exterior surface of at least 2.99 m
2
.
If any portion of the enclosure is not able to transfer heat, do not include that
value in the calculation.
Because the minimum cabinet depth to house the Kinetix 5700 system
(selected for this example) is 300 mm (11.8 in.), the cabinet needs to be
approximately 1500 x 700 x 300 mm (59.0 x 27.6 x 11.8 in.) HxWxD.
1.5 x (0.300 x 0.70) + 1.5 x (0.300 x 2.0) + 1.5 x (0.70 x 2.0) = 3.31 m
2
Because this cabinet size is considerably larger than what is necessary to house
the system components, it can be more efficient to provide a means of cooling
in a smaller cabinet. Contact your cabinet manufacturer for options available to
cool your cabinet.
Metric Standard English
Where T is temperature difference between inside air
and outside ambient (°C), Q is heat generated in
enclosure (Watts), and A is enclosure surface area (m
2
).
The exterior surface of all six sides of an enclosure is
calculated as:
Where T is temperature difference between inside air
and outside ambient (°F), Q is heat generated in
enclosure (Watts), and A is enclosure surface area (ft
2)
.
The exterior surface of all six sides of an enclosure is
calculated as:
A = 2dw + 2dh + 2wh A = (2dw + 2dh + 2wh) /144
Where d (depth), w (width), and h (height) are in
meters. Where d (depth), w (width), and h (height) are in
inches.
A =
0.38Q
1.8T - 1.1
A =
4.08Q
T - 1.1
A =
0.38 (416)
1.8 (30) - 1.1
= 2.99 m
2