356
Estimating Times and Pulses for Acceleration/Deceleration
Appendix B
A) Calculate the deceleration rate to reduce the speed from 400 pps to 0 pps in 500 ms.
Deceleration rate (pps
2
) = 400 pps/0.5 s = 800 pps
2
B) Calculate the time it takes to decelerate from 10,000 pps to 0 pps at this deceleration rate.
Time (s) = 10,000 pps/800 pps
2
= 12.5 s = 12,500 ms
C) Calculate the amount of movement required to decelerate from 10,000 pps to 0 pps within this amount of
time (12,500 ms).
Movement amount (pulses) =
= 62,500 pulses
D) Calculate the deceleration starting limit position at which the speed can be changed.
Deceleration starting limit position = 216,000
−
62,500 = 153,500 pluses
In this case, the speed change was attempted at around 193,000 pulses so the above deceleration starting
limit position has been exceeded and the speed change will not be possible. However, at less than 153,500
pulses, the speed can be changed as shown in
Figure 2
.
12.5 s
×
10,000 pps
2
Summary of Contents for CJ1W-C113 - REV 02-2008
Page 2: ...CJ1W NC113 213 413 133 233 433 Position Control Units Operation Manual Revised February 2008 ...
Page 3: ...iv ...
Page 13: ...xiv ...
Page 15: ...xvi ...
Page 19: ...xx ...
Page 27: ...xxviii Conformance to EC Directives 6 ...
Page 43: ...16 Control System Principles Section 1 7 ...
Page 47: ...20 Basic Procedures Section 2 ...
Page 139: ...112 Examples of Parameter Settings Section 4 9 ...
Page 173: ...146 Transferring Data with CX Position Section 5 7 ...
Page 223: ...196 Sample Program Section 7 7 ...
Page 259: ...232 Sample Program Section 8 10 ...
Page 293: ...266 Easy Backup Function Ver 2 0 or later Section 9 11 ...
Page 369: ...342 Reading Error Information with CX Position Section 11 8 ...
Page 385: ...358 Common Parameter Area Appendix C ...