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Page 11-37
Finally, we eliminate the –1/16 from position (1,2) by using:
16 Y # 2#1
@RCIJ
1
0
0
2 0 1 0
0
1
0
-1 0 0 1
0
0
1
1 1 0 0
We now have an identity matrix in the portion of the augmented matrix
corresponding to the original coefficient matrix A, thus we can proceed to
obtain the solution while accounting for the row and column exchanges coded
in the permutation matrix
P
. We identify the unknown vector
x
, the modified
independent vector
b
’ and the permutation matrix
P
as:
The solution is given by
P
⋅
x
=
b
’, or
Which results in
Step-by-step calculator procedure for solving linear systems
The example we just worked is, of course, the step-by-step, user-driven
procedure to use full pivoting for Gauss-Jordan elimination solution of linear
equation systems. You can see the step-by-step procedure used by the
calculator to solve a system of equations, without user intervention, by setting
the step-by-step option in the calculator’s CAS, as follows:
.
0
0
1
1
0
0
0
1
0
,
1
1
2
'
,
=
−
=
=
P
b
x
Z
Y
X
.
1
1
3
0
0
1
1
0
0
0
1
0
−
=
⋅
Z
Y
X
.
1
1
3
−
=
X
Z
Y
Содержание 49g+
Страница 1: ...hp 49g graphing calculator user s guide H Edition 4 HP part number F2228 90006 ...
Страница 197: ...Page 5 30 LIN LNCOLLECT POWEREXPAND SIMPLIFY ...
Страница 377: ...Page 11 55 Function KER Function MKISOM ...
Страница 457: ...Page 13 26 In the right hand side figure above we are using the line editor to see the series expansion in detail ...
Страница 775: ...Page 26 10 the location of the backup battery in the top compartment at the back of the calculator ...
Страница 838: ...Page L 5 ...