HP 49g+, Руководство пользователя, Страница: 358 / 862

Page 11-36
0 3 2 -1 1 0 0
0 25/8 0 -25/82 0 0 1
Checking the pivot at position (2,2), we now find that the value of 25/8, at
position (3,2), is larger than 3. Thus, we exchange rows 2 and 3 by using:
2#3 L @RSWP
1 -1/16 1/2 41/16 0 1 0
0 25/8 0 -25/8 0 0 1
0
3 2 -1 1 0 0
Now, we are ready to divide row 2 by the pivot 25/8, by using
³ 8/25™#2 L @RCI
1 -1/16 1/2 41/16
0 1 0
0 1 0 -1
0 0 1
0 3 2 -1
1 0 0
Next, we eliminate the 3 from position (3,2) by using:
3\#2#3 @RCIJ
1 -1/16 1/2 41/16
0 1 0
0 1 0 -1
0 0 1
0 0 2 2
1 0 0
Having filled with zeroes the position below the pivot, we proceed to check
the pivot at position (3,3). The current value of 2 is larger than ½ or 0, thus,
we keep it unchanged. We do divide the whole third row by 2 to convert the
pivot to 1, by using:
2Y3 @RCI
1 -1/16 1/2 41/16
0 1 0
0 1 0 -1
0 0 1
0 0 1 1
1 0 0
Next, we proceed to eliminate the ½ in position (1,3) by using:
2 Y \#3#1 @RCIJ
1 -1/16 0 33/16
0 1 0
0 1 0 -1
0 0 1
0 0 1 1
1 0 0