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Appendix B
Estimating Times and Pulses for Acceleration/Deceleration
252
Example
In this example, numeric settings are entered for the operation pattern shown below.
Speed (pps)
Time (ms)
T
D
T
U
T
AU
T
AD
P
D
P
U
35000
30000
5000
Maximum speed setting:
V
M
= 35,000 pps
Acceleration time setting:
T
AU
= 400 ms
Deceleration time setting:
T
AD
= 550 ms
Acceleration time (T
U
) =
35000 – 5000
Acceleration pulses (P
U
) =
(V
H
+ V
L
) x T
U
2
= 5827 (pulses)
=
(30000 + 5000) x 333 x 10
–3
2
x 400 x
5
6
x 10
–3
= 333 (ms)
Approx. 5800 pulses
(V
H
+ V
L
) x T
D
2
= 8015 (pulses)
=
(30000 + 5000) x 458 x 10
–3
2
Approx. 8000 pulses
Deceleration time (T
D
) =
Deceleration pulses (P
D
) =
V
H
– V
L
V
M
– V
L
T
AU
=
30000 – 5000
10
–3
=
x 400
35000 – 5000
x 550 x
5
6
x 10
–3
= 458 (ms)
V
H
– V
L
V
M
– V
L
T
AD
=
30000 – 5000
10
–3
=
x 550
Summary of Contents for C200HW
Page 1: ...Cat No W334 E1 04 Position Control Units SYSMAC C200HW NC113 NC213 NC413 ...
Page 2: ...C200HW NC113 NC213 NC413 Position Control Units Operation Manual Revised July 2003 ...
Page 3: ...iv ...
Page 5: ...vi ...
Page 285: ...Cat No W334 E1 04 C200HW NC113 NC213 NC413 Position Control Units OPERATION MANUAL ...