Cross-polarizing as polarizing quantity
Table 100:
Equations for calculating angle difference for cross-polarizing method
Faulted
phases
Used
fault
current
Used
polarizing
voltage
Angle difference
A
I
A
V
BC
ANGLE
A
V
I
BC
A
RCA
o
_
(
) -
(
) -
=
+
ϕ
ϕ
ϕ
90
GUID-330CBC28-7CE9-431A-9EC2-8590092DDAFF-ANSI V1 EN
B
I
B
V
CA
ANGLE
B
V
I
CA
B
RCA
o
_
(
) -
(
) -
=
+
ϕ
ϕ
ϕ
90
GUID-3D93A608-FA6D-4F3E-9264-19776122A8E1-ANSI V1 EN
C
I
C
V
AB
ANGLE
C
V
I
AB
C
RCA
o
_
(
) -
(
) -
=
+
ϕ
ϕ
ϕ
90
GUID-03176C00-8F5C-4791-A92C-9DBC0BA47EBF-ANSI V1 EN
A - B
I
A
- I
B
V
BC
- V
CA
ANGLE
A
V
V
I
I
BC
CA
A
B
RCA
o
_
(
-
) -
(
-
) -
=
+
ϕ
ϕ
ϕ
90
GUID-FA1C82F1-94F6-4669-8303-D465948F0611-ANSI V1 EN
B - C
I
B
- I
C
V
CA
- V
AB
ANGLE
B
V
V
I
I
CA
AB
B
C
RCA
o
_
(
-
) -
(
-
) -
=
+
ϕ
ϕ
ϕ
90
GUID-6D5785FC-2D25-48F9-B5D6-BD4E12A440E8-ANSI V1 EN
C - A
I
C
- I
A
V
AB
- V
BC
ANGLE
C
V
V
I
I
AB
BC
C
A
RCA
o
_
(
-
) -
(
-
) -
=
+
ϕ
ϕ
ϕ
90
GUID-B1524B24-5D74-4E0F-9432-7D19AC5A18C3-ANSI V1 EN
The polarizing quantity is rotated with 90 degrees. The characteristic angle is assumed to
be ~ 0 degrees.
GUID-56AF9F5B-BFEA-4775-865F-2C76D9D3BCCC-ANSI V1 EN
Figure 70:
Single-phase ground fault, phase A
1MRS240050-IB C
Section 4
Protection functions
REF615R
147
Technical Manual
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