Eaton ELC-PB, Programming Manual

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3 . I n s t r u c t i o n S e t
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3. Note the result of the first execution:
a) The actual output number 49,200 – estimated output number 50,000 = -800 (a negative
value). A negative value indicates that the entire execution finished early and has not
completed.
b) Try shortening the acceleration time (D1343) to 250ms and the deceleration time (D1348)
to 550ms.
4. The result of the second execution:
100KHz
D1340
D1348 D1343
X0 Off --> On
Frequency
Y0 stops output
Time
Number
Estimated number of output pulses: 50,000
Actual number of output pulses (D1336, D1337) = K50,020
5. Note the result of the second execution:
a) The actual output number 50,020 – estimated output number 50,000 = 20
b) 20 x (1/200Hz) = 100ms (idle time)
c) 100ms is an appropriate value. Therefore, set the acceleration time to 250ms and the
deceleration time to 550ms.
Program Example 2:
1. Assume the feedback of the encoder is an A/B phase input and we use the C251 high speed
counter (reset the counter before execution); target number of feedbacks = 50,000; target
output frequency = 100KHz; Y0, Y1 (CH0) as output pulses; start/end frequency (D1340) =
200Hz; acceleration time (D1343) = 300ms; deceleration time (D1348) = 600ms; precentage
value (D1198) = 100; current number of output pulses (D1336, D1337) = 0.