
5-24
TI 71M01D06-01EN 3rd Edition: 2012.12.01
3
3
8
.
0
2
1
×
×
+
×
×
×
×
×
=
in
f
L
in
f
m
p
E
P
D
E
P
T
N
I
η
π
3
)
(
1
p
rms
I
I
=
3
3
)
(
2
2
2
×
×
+
×
×
×
+
×
=
in
f
L
in
f
m
LL
LB
E
P
D
E
P
T
T
N
I
η
π
cy
rms
rms
in
t
t
I
t
I
I
2
2
2
1
2
)
(
1
)
(
×
+
×
=
A
I
17
.
4
3
230
5
.
0
45
3
230
5
.
0
6
.
0
)
0
50
(
05
.
1
2
2
=
×
×
+
×
×
×
+
×
=
π
Obtain the maximum current
lp
at acceleration from the motor torque and maximum velocity.
The motor efficiency varies with the velocity and torque. Here it is estimated at 60%. Note that
80% of the maximum torque is used for the motor torque. Since 3-phase input is used, the
input current per phase is multiplied by a factor of
3
1
.
Obtain the effective current at acceleration
I
1 (rms)
:
Obtain the current
I
2
at a constant velocity:
Obtain the effective input current
I
in (rms)
:
Example of Calculation
The rated currents of a circuit breaker and filter are calculated under the following operating
conditions:
Obtain the maximum current
l
p
:
Obtain the effective current at acceleration
l
1 (rms)
:
Obtain the current at a constant velocity
l
2
:
Obtain the effective input current
l
in (rms)
:
Thus, the rated current is "4A."
Be sure to verify that the value of
l
p
is within the operation characteristic curve for the selected
circuit breaker and fuse.
N
: Maximum motor velocity
(rps)
T
: Motor torque
(N-m)
D
L1
: Drive loss at acceleration
(W)
D
L2
: Drive loss at a constant velocity (W)
η
m
: Motor efficiency 60%
P
f
: Power
factor
0.5
E
in
: Power supply input voltage
(V)
T
LB
: Bearing torque Torque/10
(N-m)
T
LL
: Load torque
(N-m)
Motor operation condition
Drive current:
50 A
Motor torque:
500 N-m
Maximum velocity:
1.5 rps
Acceleration/deceleration time: 50 ms
Constant velocity time:
100 ms
Stop time:
100 ms
Cycle time:
300 ms
Power supply input voltage: 230 V
Load friction:
0 N-m
A
I
p
75
.
32
3
230
5
.
0
300
3
230
5
.
0
6
.
0
8
.
0
500
5
.
1
2
=
×
×
+
×
×
×
×
×
×
=
π
A
I
rms
9
.
18
3
75
.
32
)
(
1
=
=
A
I
rms
in
95
.
13
3
.
0
1
.
0
17
.
4
05
.
0
75
.
32
2
2
)
(
=
×
+
×
=