383
Example:
Suppose PA39 is set to 0100h and PA14 is set to
512, The number of pulses output by the linear motor
per PL42 length is (PL42 * 100000 / PL05) / 512
(pulse/PL42[mm]), The number of pulses output per
revolution of the rotary motor is the number of pulses
per revolution / 512 (pulse/rev).
PL05
Encoder resolution:
If PL01=1, PL05 unit is
3
-
10
um/pulse.
If PL01=2, PL05 unit is pulse/rev.
All
1000
1
~
2
29
-1
Refer
to
PL05
PL06
Reserved
-
-
-
-
Содержание SDP Series
Страница 33: ...20 400V series DC 24V Power supply Note terminal P N cannot be grounded ...
Страница 42: ...29 2 CN1 connector male Front view Side view Rear view CN1 wiring terminal on the back of CN1 1 26 50 25 ...
Страница 45: ...32 4 The last step is to fasten the screw of housing ...
Страница 203: ...190 It is recommended that the user performs torque position mode switching after motor is stopped completely ...
Страница 385: ...372 ...
Страница 405: ...392 ...
Страница 499: ...486 SME L040 SME L075 SME L100 SME L150 ...
Страница 500: ...487 SME L200 SME L300 SME M100 SME M150 ...
Страница 509: ...496 When the load reaches 300 the operation time is 5 51 seconds ...
Страница 541: ...528 Middle inertia power cable Middle inertia 2KW 3KW 400V High inertia power cable 1 8KW 2 9KW 4 4KW 5 5KW 7 5KW ...
Страница 555: ...542 14 5 Manual version and revision history Manual version V1 00 Release month July 2022 ...