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Voltage Umax, ignoring the CT saturation during the fault is calculated using
First, voltage U
max
, ignoring the CT saturation during the fault, is calculated with
the equation
U
I
n
R
R
R
I
n
R
k
in
in
m
s
k
in
s
max
max
max
=
×
+
+
(
)
≈
×
(Equation 218)
I
kmaxin
Maximum fault current inside the zone, in primary amps
n
Turns ration of the CT
R
in
Internal resistance of the CT in ohms
R
m
Resistance of the longest loop of the CT secondary circuit, in ohms
R
s
Resistance of the stabilized resistor, in ohms
The peak voltage
ȗ
, which includes the CT saturation, is estimated by using
(given by P. Mathews 1955).
û
U
U
U
kn
kn
=
−
(
)
2 2
max
(Equation 219)
U
kn
Knee point voltage of the CT
The VDR is recommended when the peak voltage û ≥ 2kV, which is the insulation
level for which the IED is tested.
For example, the maximum fault current in case of a fault inside the zone is 12.6 kA
in primary, CT is of 1250/5 A, that is, ratio n = 240, and knee point voltage is 81 V.
The stabilizing resistor is 330 Ohms.
U
A
V
max
=
⋅
Ω =
12600
240
330
17325
(Equation 220)
˘
.
u
kV
=
⋅
⋅
−
(
)
≈
2 2 81 17325
81
3 34
(Equation 221)
As the peak voltage
ȗ
= 3.2 kV, VDR must be used. In some cases, VDR can be
avoided if R
s
is smaller. The value of R
s
depends on the protection relay operation
current and stabilizing voltage. Thus, a higher setting in the protection relay must
be used or the stabilizing voltage lowered.
Flux-balancing principle
When the function block is used with the flux-balancing principle, there are no extra
requirements for the measuring devices. The core-balance transformers used in an
ordinary overcurrent protection are adequate here as well.
Protection functions
1MRS759142 F
814
REX640
Technical Manual