Then a fault in A has to be applied and the through fault current I
fA
has to be calculated,
. In order to get the maximum through fault current, the minimum value for Z
B
and the maximum value for Z
A
have to be considered.
ANSI10000276-1-en.vsd
~
~
Z
A
Z
B
Z
L
A
B
IED
I
fA
Fault
ANSI10000276 V1 EN
Figure 83:
Through fault current from B to A: I
fA
The IED must not trip for any of the two through fault currents. Hence the minimum
theoretical current setting (Imin) will be:
fA
fB
Imin MAX(I , I )
³
EQ1 V1 EN
(Equation 100)
A safety margin of 5% for the maximum protection static inaccuracy and a safety margin
of 5% for the maximum possible transient overreach have to be introduced. An additional
20% is suggested due to the inaccuracy of the instrument transformers under transient
conditions and inaccuracy in the system data. The minimum primary setting (Is) for
SPTPIOC (50) is then:
s
I
1.3 Imin
³
×
EQ2 V1 EN
(Equation 101)
The protection function can be used for the specific application only if this setting value
is equal to or less than the maximum fault current that the IED has to clear, fault current
(I
F
Section 7
1MRK 506 334-UUS A
Current protection
176
Application manual
Summary of Contents for REL650 series
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Page 99: ...IED IED ANSI05000460 V2 EN 1MRK 506 334 UUS A Section 4 Analog inputs 93 Application manual...
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