S
S
o
o
l
l
u
u
t
t
i
i
o
o
n
n
o
o
f
f
m
m
a
a
t
t
r
r
i
i
x
x
e
e
q
q
u
u
a
a
t
t
i
i
o
o
n
n
s
s
Solve for the value of X in
A
(
I
−
2
X
)
=
B
−
⎛
2
3
⎞
⎛
3
2
⎞
where
A
= ⎜
B
= ⎜
⎟
⎝ −
1 5
⎠
⎟
,
⎝
1
4
⎠
The algebraic calculation for this process is shown
above right. Having done this, we will now see how
to calculate this result on the calculator.
Store the values of A
and B into
M1
and
M2
respectively.
Finally use the
HOME
view to calculate the answer, using the function
IDENMAT(2)
to produce a 2x2 identity matrix, and making sure to store
the result into
M3
.
In this case the result is a horrible decimal. The fractional equivalent can
be found by setting the
MODES
view to
Decimal 6
and then re
evaluating, as shown right. From this it can be seen that the common
denominator seems to be 26, so multiplying
M3
by 26 will give a final
result of:
1
⎛
1
22
⎞
X
=
⎜
26
⎝ −
5
7
⎠
⎟
A
(1 2
X
)
=
B
−
1 2
X
A B
−
=
−
1
−
1
−
2
X
A B
I
=
−
−
1
−
1
X
=
(
A B I
)
−
2
307