
Now press
and you will see the calculator find the nearest
solution to your guess. Finish by pressing
to verify that the solution
is valid. See page 106 for more information regarding this.
Obviously the next step is to change back to the
PLOT
view, move the
cursor near to the second intersection and
for that one too.
If we now change the active variable then there is an immediate change
in the
PLOT
view to reflect this.
Change back to the
NUM
view and restore the variables to the original
values, this time leaving the highlight on
C
.
Since the active variable is now
C
, substitution of all other values means
that
A B
C
⋅ +
C
=
0 5
*
2
+ = ⋅
5*
B
becomes
0 4
⋅
. In this case both sides
are linear and this is shown in the
PLOT
view. Notice that the axis label
is now
C
. This would have only one solution and there would be no
need to supply any particular starting value.
If we duplicate this process for
A
then substitution of values means that
*
2
+ = ⋅
5*
B
becomes
A
1
0 5
A B
C
− =
⋅
. Both sides are still linear,
although not the same linear equations as before, and this is shown in
the
PLOT
view. Notice that the axis label is now
A
.
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