horsch Leeb 5.280 VL, Руководство по эксплуатации

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Calculating filling / refill
quantities
NOTE
Use the Filling table for residual areas to calculate
the required refill quantity for the last spraying
mixture container filling.
Example 1: Filling quantities
The following is known:
Rated tank volume 264 gal lqd
Residual quantity in tank 0 gal lqd
Required water 43 gal lqd/ac
Required amount of chemical per ha
Product A 3 lbs
Product B 0.3 gal lqd
Question:
How many gal lqd (l) of water, how many lbs (kg
of product A and how many gal lqd (l ) of product
B do you have to fill in if the area to be treated
is 6.2 acres?
Calculation formula and solution
Component [quantity/ac] x area [ac]
= required quantity [gal] or [lbs]
Water: 43 gal lqd/ac x 6.2 ac = 267 gal lqd
Product A: 1.3 lbs/ac x 6.2 ac = 8 lbs
Product B: 0.11 gal/ac x 6.18 ac = 0.67 gal lqd
Example 2: Addition of product, area
The following is known:
Rated tank volume 264 gal lqd
Residual quantity in tank 53 gal lqd
Required water 53.5 gal/ac
Recommended concentration 0.15% gal/gal or
lbs/gal
Question 1:
How many gal lqd or lbs preparation must be
metered for one container filling?
Calculation formula and answer to
question 1:
Water refill quantity [gal lqd] x concentration [%]
100
= preparation addition [gal lqd] or [lbs]
(264-53) [gal lqd] x 0.15 [% gal/gal or lbs/gal]
100
= 0.3 [gal lqd] or [lbs]
Question 2:
How large is the area to be treated in ac, which
can be treated with one filling, if the tank can
be sprayed down to a residual quantity of
5.3 gal lqd?
Calculation formula and answer to
question 2:
available amount of chemical [gal lqd] -
residual quantity [gal lqd]
required water [gal lqd/ac]
= area [ac]
264 [gal lqd] (rated volume) -
5.3 [gal lqd] (residual quantity)
53.5 [gal lqd/ac] (required water)
= 4.84 [ac]
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