ICPDAS
I-8092F Software User Manual
106
Fig. A-25 shows the circular interpolation of a real circle with radius 10000 in a trapezoidal
driving. The user should calculate the decelerating point before driving because the automatic
deceleration will not be active. In the figure, the circle tracks through all the 8 quadrants: 0~7. In
quadrant 0, Y axis is the short axis and it’s displace is about 10000 / 2=7071
The total output pulses numbers of the short axis are 7010x8=56568. Furthermore, if the
initial speed is 500PPS, and will be accelerated to 20KPPS after 0.3 SEC, the acceleration will be
(20000-500) /0.3 = 65000PPS/SEC. And the output pulses during acceleration will be
(500+20000) x 0.3/2=3075. Thus, if we set the deceleration as same as the acceleration, the
manual decelerating point will be 56568-3075=53493.
Fig. A-25 Calculation of manual deceleration point for circular interpolation
Note
: 1. This formula cannot be used in the constant vector speed driving.
2. In circular interpolation only manual deceleration in trapezoidal driving is available;
the automatic deceleration in S-curve driving is not available.
