The calculations show that the largest residual current from the transformer = 1.2
kA.
To assure selectivity the setting must fulfil:
I
high,set
≥ 1.2 · k · 3I
0 max
which gives about 1 500 A ,where k is the transient overreach (due to the fault current
DC-component) of the overcurrent function. For the four step residual overcurrent
function; k = 1.05.
2.
Set
t1
to
0.4 s
Characterist1
:
ANSI Def.Time
As the protection should be set for a time delay of 0.4 s the selectivity to the line
protections should be assured. Therefore ground-faults should be calculated where
the fault point on the lines is at zone 1 reach (about 85 % out on the line).
3.1.6.3
Calculating settings for step 2
1.
Set
Pickup2
to
400%
of
IBase
, corresponding to 956 A
To assure that step 2 detects all ground-faults on the outgoing lines ground-faults
calculations are made where single phase-faults and phase-to-phase-to ground-
faults are applied to the adjacent busbars.
1
1
1
3
3
Ph-Ph
145 kV
22 kV
ANSI11000130-1-en.vsd
REC650
Y
Y
Y
51N_67N
ANSI11000130 V1 EN
Figure 12:
Fault calculation for sufficient reach of the 145 kV residual
overcurrent protection
The minimum residual current to detect works out as 3I
0AB,min
= 1.0 kA.
2.
Set
t2
to
0.8 s
Characteristic2
:
ANSI Def.Time
The delay of
Pickup2
should be set longer than the distance protection zone 2
(normally 0,4 s). 0.8 s is proposed.
Section 3
1MRK 511 286-UUS A
REC650 setting examples
54
Application manual
Содержание REC650 ANSI
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