Basic Electricity
1:16
CP 1 – Cathodic Protection Tester Course Manual
©
NACE International, 2000
02/01/05
I
T
E
I
1
I
2
R
2
I
4
R
4
I
T
I
3
R
1
R
3
–
+
Figure 1.8 Series and Parallel Circuits Combined
Given
E = 20 V
R
1
= 5
Ω
R
2
= 4
Ω
R
3
= 2
Ω
R
4
= 0.95
Ω
First, reduce the parallel part of the circuit to a single resistance
using the same formula as shown for Figure 1.7:
Ω
=
=
Ω
+
Ω
+
Ω
=
05
.
1
95
.
0
1
2
1
4
1
5
1
1
R
T
We now have an equivalent series circuit of two resistors, 1.05
Ω
and 0.95
Ω
for a total resistance of 2.00
Ω
.
Summary of Contents for CP 1
Page 1: ...CP 1 Cathodic Protection Tester Course Manual February 2005 NACE International 2000 ...
Page 265: ......
Page 266: ......
Page 267: ......
Page 268: ......
Page 301: ...RP0169 2002 32 NACE International ISBN 1 57590 035 1 ...
Page 535: ...TM0101 2001 24 NACE International ISBN 1 57590 137 4 ...