Basic Electricity
1:12
CP 1 – Cathodic Protection Tester Course Manual
©
NACE International, 2000
02/01/05
For example, consider the following circuit, where:
E
T
= Total Voltage Across the Circuit
R
T
= Total Resistance in the Circuit
I
T
= Total Current in the Circuit
E
1
E
2
R
1
R
2
R
3
I
E
2
E
1
R
3
R
2
R
1
Figure 1.6 Series Circuit
Given
E
1
= 5 V
E
2
= 5 V
R
1
= 5
Ω
R
2
= 3
Ω
R
3
= 2
Ω
Ω
=
Ω
+
Ω
+
Ω
=
10
2
3
5
R
T
A
1
10
V
10
R
E
I
T
=
Ω
=
=
I
1
= 1 A
I
T
R
1
= 1 A x 5
Ω
= 5 V
I
2
= 1 A
I
T
R
2
= 1 A x 3
Ω
= 3 V
I
3
= 1 A
I
T
R
3
= 1 A x 2
Ω
= 2 V
Total IR Drop = 10 V
OR
IR
T
= 1 A x 10
Ω
= 10 V
E
T
= 10
V
Note that Kirchhoff’s Voltage Law is fulfilled.
Summary of Contents for CP 1
Page 1: ...CP 1 Cathodic Protection Tester Course Manual February 2005 NACE International 2000 ...
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Page 301: ...RP0169 2002 32 NACE International ISBN 1 57590 035 1 ...
Page 535: ...TM0101 2001 24 NACE International ISBN 1 57590 137 4 ...