InteliMains 210 Global Guide
90
Image 5.24 Run hours equalization - case #2
step
0
1
2
3
4
5
6
7
8
9
10
11
12
13
RHE1
0
11
11
11
11
33
33
33
33
55
55
55
55
77
RHE2
0
0
11
11
22
22
33
33
44
44
55
55
66
66
RHE3
0
0
0
22
22
22
22
44
44
44
44
66
66
66
Run G1 (ΔRHE1)
0
11
0
0
0
22
0
0
0
22
0
0
0
22
Run G2 (ΔRHE2)
0
0
11
0
11
0
11
0
11
0
11
0
11
0
Run G3 (ΔRHE3)
0
0
0
22
0
0
0
22
0
0
0
22
0
0
Case #3:
Gen-set 1 running hours = 250 -> running hours considered in RHE = 100 (150-RunHoursBase)
Gen-set 2 running hours = 450 -> running hours considered in RHE = 200 (250-RunHoursBase)
Gen-set 3 running hours = 750 -> running hours considered in RHE = 250 (500-RunHoursBase)
The gen-set 1 has the lowest RHE1 = 100 h. By applying the SwapTime formula, we get the run time of gen-set
2 before next swapping:
SwapTimeG1 = 200 – 100 + 10 + 1 = 111
Till the step 5, the evolution of the gen-set swapping is the same as in the case #1, just gen-set 1 and gen-set 2
involve. In the step 6 the gen-set 2 can run only 17 hours (previously 22 hours) because the gen-set 3 involves.
The evolution of RHE1, RHE2 and RHE3 is shown on the figure below.
Image 5.25 Run hours equalization - case #3
