GE Multilin
T60 Transformer Protection System
D-1
APPENDIX D
D.1 IEC 60870-5-103
D
APPENDIX D IEC 60870-5-103 COMMUNICATIONSD.1IEC 60870-5-103
D.1.1 OVERVIEW
IEC 60870-5-103 is defined as a companion standard for the informative element of the protection equipment. IEC 60870-
5-103 defines communication for a serial, unbalanced link only. Communication speeds are defined as either 9600 or
19200 baud.
This manual assumes basic knowledge of the IEC 60870-5-103 protocol and the standard IEC 60870 documents relating to
the protocol.
Standard IEC 60870 documents relating to IEC 60870-5-103:
•
IEC 60870-5-1 Transmission frame formats
•
IEC 60870-5-2 Link transmission procedures
•
IEC 60870-5-3 General structure of application data
•
IEC 60870-5-4 Definition and coding of application information elements
•
IEC 60870-5-5 Basic application functions
•
IEC 60870-5-6 Conformance testing guidelines
An IEC 60870-5-103 device is required to provide an interoperability table. Interoperability means that any required applica-
tion data in the device, which can be coded into an IEC 60870-5-103 data type, can be mapped into the IEC 60870-5-103
address space. This data is recognized by any IEC 60870-5-103 master.
D.1.2 FACTOR AND OFFSET CALCULATION TO TRANSMIT MEASURAND
The general formula for the transmitted value is Xt = a * X + b
where X is the measurand, a is the multiplication factor, b is the offset and Xt is the value transmitted.
The conditions for determining a and b, when the values exceed the range are:
4096 = a*Xmax + b (Xmax is the maximum value for the measurand)
-4095 =a*Xmin + b (Xmin is the minimum value for the measurand)
By solving the above system of equations for a and b, we find that:
a = 8191 / (Xmax - Xmin)
b = -4096 * (Xmax + Xmin) / (Xmax - Xmin)
So
Xt = 8191/(Xmax - Xmin)) * X - 4096 * (Xmax + Xmin) / (Xmax - Xmin)
We may further simplify the above formula for situations where:
1)
Xmin = -Xmax (positive and negative values) :
Xt = (8191/2*Xmax) * X
a = 4096/Xmax
b = 0
2)
If Xmin = 0 (only positive values)
Xt = (8191/Xmax) * X - 4096
a = 2 * 4096/Xmax
b = -4096
To calculate Xmax, one needs to know the rated value for the specific type of measurand.
Xmax = 2.4 * Xrated
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Страница 34: ...1 20 T60 Transformer Protection System GE Multilin 1 5 USING THE RELAY 1 GETTING STARTED 1 ...
Страница 118: ...3 48 T60 Transformer Protection System GE Multilin 3 3 DIRECT INPUT OUTPUT COMMUNICATIONS 3 HARDWARE 3 ...
Страница 146: ...4 28 T60 Transformer Protection System GE Multilin 4 3 FACEPLATE INTERFACE 4 HUMAN INTERFACES 4 ...
Страница 490: ...5 344 T60 Transformer Protection System GE Multilin 5 10 TESTING 5 SETTINGS 5 ...
Страница 522: ...6 32 T60 Transformer Protection System GE Multilin 6 5 PRODUCT INFORMATION 6 ACTUAL VALUES 6 ...
Страница 536: ...7 14 T60 Transformer Protection System GE Multilin 7 1 COMMANDS 7 COMMANDS AND TARGETS 7 ...
Страница 538: ...8 2 T60 Transformer Protection System GE Multilin 8 1 DIRECTIONAL PRINCIPLE 8 THEORY OF OPERATION 8 ...
Страница 568: ...10 12 T60 Transformer Protection System GE Multilin 10 6 DISPOSAL 10 MAINTENANCE 10 ...
Страница 596: ...A 28 T60 Transformer Protection System GE Multilin A 1 PARAMETER LISTS APPENDIX A A ...
Страница 716: ...B 120 T60 Transformer Protection System GE Multilin B 4 MEMORY MAPPING APPENDIX B B ...
Страница 762: ...E 10 T60 Transformer Protection System GE Multilin E 1 IEC 60870 5 104 PROTOCOL APPENDIX E E ...
Страница 774: ...F 12 T60 Transformer Protection System GE Multilin F 2 DNP POINT LISTS APPENDIX F F ...
Страница 785: ...GE Multilin T60 Transformer Protection System H 9 APPENDIX H H 2 ABBREVIATIONS H Z Impedance Zone ...