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189
)
(
2
1
LA
R
L
=R(111°55′47″-2 * 18°20′06″)
=100( 75°15′35″
180
)
=131.353 m
⑼
Calculation of the coordinate KA2
2
2
1
2
cos
D
N
N
IP
KA
2
2
1
2
sin
D
E
E
IP
KA
Bearing from IP1 to IP2
2
322°07′30.1″
N
KA
2
1300 –(-182.468) * cos 322°07′30.1″= 1444.032 m
E
KA
2
1750 –(-182.468) * sin 322°07′30.1″= 1637.976 m
⑽
calculate coordinate of feature point BC, EC of Arch length
Arch Length
IA
R
CL
IA= 95°52′11″
So
CL=200 * 95°52′11″*
180
=334.648 m
Tangent length
)
2
tan(
IA
R
TL
200 * tan(95°52′11″/ 2) =221.615 m
Calculate coordintes of each points
：
2
2
cos
TL
N
N
IP
BC
2
2
sin
TL
E
E
IP
BC
3
2
cos
TL
N
N
IP
EC
3
2
sin
TL
E
E
IP
EC
Here:
2
(bearing from IP1 to IP2) = 322°07′30.1″
3
(Bearing from IP2 to EP) = 57°59′40.6″
N
BC
1750 - 221.615 * cos322°07′30.1″ =1575.068 m
E
BC
1400 - 221.615 * sin322°07′30.1″ =1536.058 m
N
EC
1750 –(-221.615) * cos57°59′40.6″=1867.456 m
E
EC
1400 –(-221.615) * sin57°59′40.6″=1587.929 m
