Mitsubishi Heavy Industries SRRM40HENG-L, Руководство пользователя

Страница: 560 / 1106

558
FDR-H
Table of bypass factor
Item
Air flow
Hi 0.035 0.032 0.039 0.085 0.035
Lo 0.021 0.020 0.023 0.060 0.023
Model
FDR 208 type FDR 258 type FDR 308 type FDR 408 type FDR 508 type
(2) Correction of cooling and heating capacity in relation to air flow rate control (fan speed)
Coefficient: 1.00 at High, 0.95 at Low
(3) Correction of cooling and heating capacity in relation to one way length of refrigerant piping
It is necessary to correct the cooling and heating capacity in relation to the one way equivalent piping length between the indoor
and outdoor units.
Equivalent piping length (1) m 5 10 15 20 25 30 35 40 45 50 55
Heating 1.0 1.0 1.0 1.0 1.0 0.995 0.995 0.99 0.99 0.985 0.985
FDR208 type 1.0 0.995 0.995 0.99 0.985 0.985 0.98
   
FDR258 type 1.0 0.995 0.99 0.985 0.98 0.975 0.97
   
1.0 0.99
0.98 0.97 0.96 0.95 0.94 0.93 0.92 0.91 0.9
1.0 0.995 0.985 0.98 0.97 0.965 0.955 0.95 0.94 0.935 0.925
1.0
0.99 0.975 0.965 0.95 0.94 0.925 0.915 0.9 0.89 0.875
1.0 0.99 0.98 0.97 0.96 0.95 0.94
   
1.0 0.995 0.985 0.98 0.97 0.965 0.955
   
1.0 0.99 0.975 0.965 0.95 0.94 0.925
   
Note (1) Equivalent piping length can be obtained by calculating as follows.
208, 258, 308 series [
φ
15.88(5/8
″
)]: Equivalent piping length = Real piping (0.10
×
Number or bends in piping)
408, 508 series [
φ
19.05(3/4
″
)]: Equivalent piping length = Real piping (0.15
×
Number of bends in piping)
[Equivalent piping length < Limitation length of 5m]
Height difference between the indoor unit and
outdoor unit in the vertical height difference
5m 10m 15m 20m 25m 30m
Adjustment coefficient 0.01 0.02 0.03 0.04 0.05 0.06
Piping length limitations
Item
Model FDR208, 258 type FDR308~508 type FDR308~508 type
Max. one way piping length 30m 50m 30m
Max. vertical height difference
Outdoor unit is higher 20m Outdoor unit is higher 30m
15m
Outdoor unit is lower 15m Outdoor unit is lower 15m
Note (1) Values in the table indicate the one way piping length between the indoor and outdoor units.
How to obtain the cooling and heating capacity
Example : The net cooling capacity of the model FDR308HEN-SA with the air flow “High”, the piping length of 15m, the outdoor unit
located 5m lower than the indoor unit, indoor wet-bulb temperature at 19.0 ˚C and outdoor dry-bulb temperature 35 ˚C is
Net cooling capacity = 7100
×
1.00
×
(0.98 - 0.01)
×
1.0 = 6887 w
Cooling
FDR308 type
(FDC308 type)
(FDC308~508 type) (FDC306~506 type)
(4) When the outdoor unit is located at a lower height than the indoor unit in cooling operation and when the
outdoor unit is located at a higher height than the indoor unit in heating operation,
the following values should be
subtracted from the values in the above table.
Factor by air
temperatures FDR308HEN-SA Air flow
“High”
Length 15m.
Height difference 5 m
FDR408 type
(FDC408 type)
FDR508 type
(FDC508 type)
FDR508 type
(FDC306 type)
FDR408 type
(FDC406 type)
FDR508 type
(FDC506 type)