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Date Code 20011026
Maintenance and Testing
7-51
SEL-321/321-1 Instruction Manual
The resistive reach of the quadrilateral distance element under test is defined by the
RG2 element setting. In this case RG2 = 5.00 secondary ohms. The impedance
measured by the relay for a ground fault is determined by the faulted phase voltage,
faulted phase current, and the residual current multiplied by the zero-sequence
current compensation factor, k0. The SEL-321 Relay uses k01M and k01A settings
to define the zero-sequence current compensation factor for all zones.
The reactance measured by the relay ground quadrilateral distance element for a
Zone 2 fault is defined by the following equation:
(
)
(
)
(
)
(
)
(
)
(
)
(
)
[
]
*
ANG
1
Z
1
I
0
k
I
I
I
Im
*
ANG
1
Z
1
I
0
k
I
V
Im
R
R
A
0
A
2
A
2
3
R
A
A
AG
∠
⋅
⋅
+
+
⋅
∠
⋅
⋅
+
=
Equation
7.20
Where:
k0 = k01M
∠
k01A° for Zone 1, 2, 3, and 4
I
A2
= negative-sequence current flowing in A-phase for the fault
I
A0
= zero-sequence current flowing in A-phase for the fault
For a fault on a radial system with no load and when testing a ground distance
element using a single current source, I
A
= I
R
, I
A2
= I
A
/3, and I
A0
= I
A
/3. Equation
7.20 can be simplified:
(
)
(
)
(
)
(
)
(
)
(
)
*
ANG
1
Z
1
0
k
1
I
I
Im
*
ANG
1
Z
1
0
k
1
I
V
Im
R
A
A
A
A
AG
∠
⋅
+
⋅
⋅
∠
⋅
+
⋅
⋅
=
Equation
7.21
Select a value for V
A
. Then it is possible to use Equation 7.21 to calculate the
magnitude and angle of I
A
required to test the Zone 2 ground quadrilateral distance
element resistive reach.
For the example, select V
A
= 40.0
∠
0°. To simplify the resistance calculation, select
the angle of I
A
= 0°. For the Zone 2 element, RG2 = 5.00
Ω
,
∠
Z1ANG = 83.97°, and
k01 = 0.726
∠
-3.69°.
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
(
)
*
42
.
82
725
.
1
I
I
Im
*
42
.
82
725
.
1
I
0
0
.
40
Im
00
.
5
*
97
.
83
1
55
.
1
725
.
1
I
I
Im
*
97
.
83
1
55
.
1
725
.
1
I
0
0
.
40
Im
00
.
5
*
97
.
83
1
69
.
3
726
.
0
1
I
I
Im
*
97
.
83
1
69
.
3
726
.
0
1
I
0
0
.
40
Im
00
.
5
A
A
A
A
A
A
A
A
A
°
∠
⋅
⋅
∠
⋅
°
∠
=
°
∠
⋅
°
−
∠
⋅
⋅
°
∠
⋅
°
−
∠
⋅
°
∠
=
°
∠
⋅
°
−
∠
+
⋅
⋅
°
∠
⋅
°
−
∠
+
⋅
°
∠
=
Equation
7.22
Because the angle of I
A
equals 0°, simplify the equation above:
(
)
(
)
°
−
∠
⋅
°
−
∠
⋅
⋅
=
42
.
82
725
.
1
Im
I
42
.
82
725
.
1
Im
I
0
.
40
00
.
5
2
A
A
Содержание SEL-321
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Страница 78: ...2 54 Specifications Date Code 20011026 SEL 321 321 1 Instruction Manual Figure 2 4 Logic Symbol Legend ...
Страница 87: ...Date Code 20011026 Specifications 2 63 SEL 321 321 1 Instruction Manual Figure 2 21 Load Encroachment Logic ...
Страница 94: ...2 70 Specifications Date Code 20011026 SEL 321 321 1 Instruction Manual Figure 2 29 Voltage Element Logic ...
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Страница 171: ...Date Code 20011026 Event Reporting 4 9 SEL 321 321 1 Instruction Manual ...
Страница 263: ...SEL DIRECTION AND POLARITY CHECK FORM ...
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