Publication DNET-UM072C-EN-P - July 2004
Determine Power Requirements
4-25
D.
[(1100 x (0.0045)) + (4 x (0.005))] x 0.25 = 1.24V
2.
Add each device’s voltage together to find the total voltage for section 1.
0.11 + 0.45 + 0.79 + 1.24= 2.59V
3.
Find the voltages for each device in section 2 using the equation for
thick cable.
SUM {[(L
n
x (0.0045)) + (N
t
x (0.005))] x I
n
} < 4.65V.
A.
[(100 x (0.0045)) + (1 x (0.005))] x 1.5 = 0.68V
B.
[(500 x (0.0045)) + (
2
x (0.005))] x 0.5 = 1.13V
4.
Add each device’s voltage together to find the total voltage for section 2.
0.68 + 1.13 = 1.81V
Since the total voltage does not exceed 4.65V in either section, the system will
operate properly - section 1 (2.59V < 4.65V) section 2 (1.81V < 4.65V).
The percent loading is found by dividing the total voltage by 4.65V.
Section 1%Loading = 2.59/4.65 = 56%
Section 2% Loading = 1.81/4.65 = 39%
D5
1.5A
D6
0.5A
Results
Содержание H Series
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Страница 144: ...Publication DNET UM072C EN P July 2004 Table of Contents iv...
Страница 170: ...Publication DNET UM072C EN P July 2004 1 26 Get Started Notes...
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Страница 212: ...Publication DNET UM072C EN P July 2004 3 18 Make Cable Connections Notes...
Страница 238: ...Publication DNET UM072C EN P July 2004 4 26 Determine Power Requirements Notes...
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