Allen-Bradley Kinetix 350, Руководство пользователя

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Rockwell Automation Publication 2097-UM002D-EN-P - April 2017 21
Install the Kinetix 350 Drive System Chapter 2
Transformer Specifications for Input Power
Enclosure Selection
This example is provided to assist you in choosing the size of the enclosure for
your Bulletin 2097 drive system. You need heat dissipation data from all
components that are planned for your enclosure to calculate the enclosure size.
See Power Dissipation Specifications on
page 22 for your drive.
With no active method of heat dissipation (such as fans or air conditioning),
either of the following approximate equations can be used.
If the maximum ambient rating of the Kinetix 350 drive system is 40 °C
(104 °F) and if the maximum environmental temperature is 20 °C (68 °F), then
T=20. In this example, the total heat dissipation is 416 W (sum of all
components in enclosure). So, in the equation below, T=20 and Q=416.
IMPORTANT Use a form factor of 1.5 for single and three-phase power (where form factor
is used to compensate for transformer, drive, and motor losses, and to
account for utilization in the intermittent operating area of the torque speed
curve).
For example, to choose the size of a transformer for the voltage
requirements of catalog number
2097-V34PR6-LM = 3 kW continuous x 1.5 = 4.5 KVA transformer.
Attribute Value (460V system)
Input volt-amperes 750VA
Input voltage 480V AC
Output voltage 120…240V AC
Metric Standard English
Where T is temperature difference between inside air
and outside ambient (°C), Q is heat that is generated in
enclosure (Watts), and A is enclosure surface area (m²).
The exterior surface of all six sides of an enclosure is
calculated as Where T is temperature difference between inside air
and outside ambient (°F), Q is heat that is generated in
enclosure (Watts), and A is enclosure surface area (ft
2)
.
The exterior surface of all six sides of an enclosure is
calculated as
A = 2dw + 2dh + 2wh A = (2dw + 2dh + 2wh) /144
Where d (depth), w (width), and h (height) are in
meters. Where d (depth), w (width), and h (height) are in
inches.
A = 0.38Q
1.8T - 1.1
A = 4.08Q
T - 1.1
A = 0.38 (416)
1.8 (20) - 1.1
= 4.53 m
2