Rules Governing the Use of the S5-115F
S5-115F Manual
It can be calculated as follows:
100
100 - Q
T
PLC cycle (OB 2, OB 13, SINEC)
= T
PLC cycle
.
where: Q=Q
2
+Q
13
+Q
SINEC
Q
2
= OB 2 execution time component of the total S5-115F execution time
Q
13
= OB 13 execution time component of the total S5-115F execution time
Q
SINEC
= SINEC L1 LAN execution time component of the total S5-115F execution time
e.g.
Call interval
Excecution time
Execution time Q
i
OB 2
OB 13
Number of SINEC L1 LAN slaves
= 2
Max. message length
= 62 bytes
Execution time component Q
SINEC,
1 LAN
= 20%
2 LANs
= 30%
Total execution time component Q
2
+Q
13
+Q
SINEC (2 LANs)
= 48 %
40 msec.
4 msec.
10 %
100 msec.
8 msec.
8 %
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
Note
•
Avoid Q>50%
•
Under worst-case conditions, please note:
Direct access commands to the interrupt DI in OB 2 may be extended by the
relevant short discrepancy time.
Example
The operating system execution time is
•
60 to 100 msec. for
-
Limited configuration with 24 V I/O modules
-
Directly driven actuators
-
30 msec. short discrepancy time
•
80 to 250 msec. for
-
Extended configuration with 220 V I/O modules
-
Indirectly driven actuators
-
30 msec. short discrepancy time
You can determine the PC cycle time in a relatively easy way in Test mode. Add a flag word to your
cyclic program and count, for example, 1000 cycles with it. If you measure the time required for
this, the mean cycle time can be determined exactly.
10-8
EWA 4NEB 811 6148-02