10.001 V * 6.5 Hz/V = 65.0065 Hz
For this example, the displayed
Hz
in the
Transducer Output
section of the
Transducer
Test Screen
should read 65.0091 Hz.
The
Accuracy
displayed in the
Transducer Output
section would be equal to the
following,
(65.0065 - 65.0000/ 65.0000) * 100 = % accuracy or
-0.01
%
If this were a 0.02 % transducer, then the firmware would compare the accuracy values
between the Setting Screen and the Test Screen and would display
PASS
in the
Transducer Output
section of the test screen..
-
155
www
. ElectricalPartManuals
. com