5.
4
(MT13 - En 2015)
System with two external door stations, a doorkeeper exchanger and two independent risers with
separators. For the calculation of the equivalent loads and equivalent impedances the following composi-
tion is assumed: building “a” with 34 video intercoms and “b” with 16.
Riser "a" with:
34 VC (EX3252C);
C
E
= 8
X
34 = 272
9
DV (DV2424Q);
C
E
= 0
X
9
=
0
-------
1
ALp (2221S = <700)
272
Load riser "a"
Riser "b" with:
16 VC (ZH1262);
C
E
= 10
X
16= 160
4
DV (DV2424Q);
C
E
= 0
X
4
=
0
-------
1
AL (2221ML = <400);
160
Load riser "b"
Common line with:
1 DM
(DM2444);
C
E
= 10
X
1 = 10
2 SM
(2231);
C
E
= 10
X
2 = 20
1 PDX (PDX2000);
C
E
= 30
X
1 = 30
2 PEp (TD2100PL);
-------
1 ALp (2221ML = <400);
60
Load common line
Composition with the following items and
calculation of the equivalent absorption load:
System with an external door
station and single riser. For the
calculation of the equivalent loads
and equivalent impedances a
composition of 43 video intercoms
is assumed.
System with two external door stations, a doorkeeper exchanger and two non-independent risers.
For the calculation of the equivalent loads and equivalent impedances the following composition is assumed:
building “a” with 34 video intercoms and “b” with
16.
Example schematics and calculation of the devices equivalent loads and impedances
SM
SM
AL
AL
VC
VC
VC
VC
VC
VC
ALp
DM
PEp
PEp
DV
DV
DV
DV
"a"
"b"
PDX
Equivalent impedance calculation:
Riser "a": 34x10(VC)+9x0(DV)+10(AL) = 350Z
E
a
Riser "b": 16x10(VC)+4x0(DV)+10(AL) = 170Z
E
b
Common line:
2x8(SM)+8(DM)+10(PDX)+10(ALp)+2x10(PEp) = 64Z
E
p
Common line + Riser "a": 350Z
E
a+64Z
E
p = 414Z
E
Common line + Riser "b": 170Z
E
b+64Z
E
p = 234Z
E
34 VC (EX3252C);
C
E
= 8
X
34 = 272
16 VC (ZH1262);
C
E
= 10
X
16 = 160
9
DV (DV2424Q);
C
E
= 0
X
9
=
0
4
DV (DV2424Q);
C
E
= 0
X
4
=
0
1
DM (DM2444);
C
E
= 10
X
1 =
10
1
PDX (PDX2000);
C
E
= 30
X
1 =
30
2
PEp (TD2100PL);
C
E
= 0
X
2
=
0
-------
1
ALp (2221S = <700)
472
Composition with the following items and
calculation of the equivalent absorption load:
43 VC (EX3252C);
C
E
= 8
X
43
= 344
11 DV (DV2424Q);
C
E
= 0
X
11
= 0
1 DL (DV2420);
C
E
= 30
X
1
= 30
1 PE (TD2100PL);
C
E
= 0
X
1
= 0
-------
1 AL (2221ML =
max.400
)
374
Composition with the following
items and calculation of the
equivalent absorption load:
Equivalent impedance calculation:
43x10(VC)+11x0(DV)+10(DL)+
10(PE)+10(AL) = 460Z
E
VC
VC
VC
VC
VC
VC
ALp
DM
PEp
PEp
DV
DV
DV
DV
"a"
"b"
PDX
Equivalent impedance calculation:
34x10(VC)+16x10(VC)+9x0(DV)+4x0(DV)+8(DM)+
10(PDX)+2x10(PEp)+10(ALp) = 548Z
E
V
I
D
E
O
I
N
T
E
R
C
O
M
S
VC
VC
VC
VC
VC
VC
AL
DL
PE
DV
4
DV
1
INSTALLATION NOTES
