Gree GMV-1015WM/G-U, Руководство по обслуживанию

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Gree GMV6 DC Inverter VRF Units Service Manual
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2.2 Refrigerant charging amount B of every module
Refrigerant charging amount B
of every module (kg(Pounds))
②
Module capacity(kW)
IDU/ODU rated
capacity
collocation ratio C
①
Quantity of
indoor unit
22.4 28 33.5 40 45 50.4 56 61.5 68
50%≤C≤70%
<4 0 0 0 0 0 0 0 0 0
≥4 0.5(1.1) 1(2.2) 1(2.2) 1(2.2) 1(2.2) 0.5(1.1) 1(2.2) 1.5(3.3) 1.5(3.3)
70%
＜
C≤90%
<4 0.5(1.1) 1(2.2) 1(2.2) 2(4.4) 2(4.4) 1.5(3.3) 2(4.4) 2(4.4) 2(4.4)
≥4 1(2.2) 1(2.2) 1(2.2) 2(4.4) 2(4.4) 2.5(5.5) 3(6.6) 3.5(7.7) 3.5(7.7)
90%
＜
C≤105%
<4 1(2.2) 1(2.2) 1(2.2) 2(4.4) 2(4.4) 2.5(5.5) 3(6.6) 3.5(7.7) 3.5(7.7)
≥4 2(4.4) 2(4.4) 2(4.4) 4(8.8) 4(8.8) 4(8.8) 5(11.0) 5(11.0) 5(11.0)
105%
＜
C≤135%
<4 2(4.4) 2(4.4) 2(4.4) 3(6.6) 3(6.6) 3.5(7.7) 4(8.8) 4(8.8) 4(8.8)
≥4 3.5(7.7) 4(8.8) 4(8.8) 5(11.0) 5(11.0)
5.5
(12.1)
6(13.2) 6(13.2) 6(13.2)
Notes:
①
Rated capacity configuration rate of indoor unit and outdoor unit C = sum of indoor unit rated
cooling capacity / sum of outdoor unit rated cooling capacity.
②
If all indoor units are all fresh air indoor units, the added refrigerant amount for each module B
is 0kg(0 LBS).
③
If all fresh air indoor units are mixed with the general VRF indoor units, charge the refrigerant
according to the refrigerant-charging method of the general indoor unit.
For example1:
Outdoor unit consists of one 28kW module and one 45kW module. Five 14kW duct type units are
used as indoor units.
IDU/ODU rated capacity collocation ratio C=14.0×5/(28.0+45.0)=96%. The quantity of included IDUs
is more than 4 sets. Please refer to the above table.
Additional refrigerant quantity B for 28kW module is 2.0 kg(4.41 LBS).
Additional refrigerant quantity B for 45kw module is 4 kg(8.82 LBS).
So, ∑Refrigerant charging amount B of every module=2.0+4=6 kg (13.23 LBS).
Suppose the Pipeline charging am ount A=∑Liquid pipe length × refrigerant charging amount of every
1m liquid pipe=20kg(44.1 LBS).
Total refrigerant charging amount R=20+6=26kg(49.83 LBS).
For example 2:
Outdoor unit is a 45kW module and the indoor unit is a 45kW fresh air unit. The quantity (B) of
refrigerant added to this module is 0kg(0 LBS).
So, ∑Refrigerant charging amount B of every module= 0kg (0 LBS).
Suppose the Pipeline charging amount A=∑Liquid pipe length × refrigerant charging amount of every
1m liquid pipe = 5kg(11.025 LBS).
Total refrigerant charging amount R = 5+0=5kg(11.025 LBS).