
The following diagram shows the required corrections of mass values
∆
m for
a few selected density values
ρ
W
. The incorrect values result from the effects of air
buoyancy. The corrections depend on the weights displayed on the balance.
Example: aluminum: conventional mass of 2 g (density 2.7)
Readout
Without air buoyancy correction
→
+ 2000.000 mg
With air buoyancy correction
→
+ 2000.
589
mg
3–6
Add the mass error to the weight
displayed on the balance
Weight displayed
on the balance (grams)
Correction
of the mass
∆
m
(milligrams)
Subtract the mass error from
the weight displayed on the balance
g
ρ
w
= 0.8 —–
cm
3
g
ρ
w
= 1.0 —–
cm
3
g
ρ
w
= 1.4 —–
cm
3
g
ρ
w
= 2.0 —–
cm
3
g
ρ
w
= 4.0 —–
cm
3
g
ρ
w
= 22.5 —–
cm
3
g
ρ
w
= 8.0 —–
cm
3
g
ρ
w
= 0.0012 —– (air)
cm
3
Density of the object
to be weighed
Содержание MC 210 S
Страница 4: ...General View of the Balances MC 210 S MC 210 P and MC 410 S 0CE 1 0...
Страница 6: ...General View of the Balances MC 5 0CE and SC 2 0CE 1 2 34 35 36 10 7 9 8 37...
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Страница 166: ...5 6 Z 14 755 320 34 10 93...
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Страница 174: ...6 4...
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