149
3
2
cos
TL
N
N
IP
EC
3
2
sin
TL
E
E
IP
EC
2
(Bearing from IP1 to IP2) = 322°07
′30.1″
3
(Bearing from IP2 to EP) = 57°59
′40.6″
N
BC
1750 - 221.615 * cos322°07
′30.1″ =1575.068 m
E
BC
1400 -
221.615 * sin322°07′30.1″ =1536.058 m
N
EC
1750
–(-221.615) * cos57°59′40.6″=1867.456 m
E
EC
1400
–(-221.615) * sin57°59′40.6″=1587.929 m
The calculated results display as below :
The coordinates and the distance are calculated as below
:
1) Compute the length of straight line
Straight line
BP·KA1=
543
.
545
)
1050
553
.
1574
(
)
000
.
1100
872
.
1249
(
2
2
m
straight line KA2·BC
005
.
166
)
976
.
1637
058
.
1536
(
)
032
.
1444
068
.
1575
(
2
2
m
straight line
EC·EP
084
.
250
)
929
.
1587
1800
(
)
456
.
1867
2000
(
2
2
m
Содержание STS-750RC Series
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