Sanding STS-750RC Series, Руководство пользователя

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147

1
=
80
64
2
2
2

= 0.32 rad

deg

0.32

180
=18°20
′06″


1
= -

2
3) Calculation of transition coordinates

2
 
A N ....)
9360 216 10
1 (
6 4 2
  
  

2
 
A E
....)
7560 1320 42 3
(
7 5 3
   
  
32 . 0 2 80
  
N ....)
9360 216 10
1 (
) 32 . 0 ( ) 32 . 0 ( ) 32 . 0 (
6 4 2
  
)
9360
4 0010734182 . 0
216
01048576 . 0
10
01024 . 0
1 ( 64
   
) 00000011 . 0 00004855 . 0 01024 . 0 1 ( 64
   

64 * 0.98981

63.348
Similarly, the value of E is:
32 . 0 2 80
  
E ....)
7560 1320 42 3
32 . 0
(
) 32 . 0 ( ) 32 . 0 ( ) 32 . 0 (
7 5 3
  
) 0 0000025 . 0 00078019 . 0 10666667 . 0 ( 64
   

6.777
This example is symmetry spiral transition N1=N2
，
E1=E2
4) Calculation of shift value R

) cos 1 (

   
R E R
18 cos 1 ( 100 777 . 6
   
R
°20′06″)

1.700
Symmetry spiral transition
R R
2 1
  
5) Calculation of Spiral Transition coordinate

sin R N
N
m
 
=63.348-100sin18°20
′06″=31.891
Symmetry spiral transition
N N
m m 2 1

6) Calculation of Tangent Distance
N
R R D
m
LA LA ec
LA
R
1 1 2 1
) cot( ) ( cos )
2
tan(
     
 
LA
111°55′47″
，
s i n
1
c o s

ec ,
tan
1
cot


D
1
100 * tan(111°55′47″/ 2) +1.7(1 / sin111°55′47″)