Omron 8U0108-E1-01, Руководство пользователя

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XtraDrive User Manual Chapter 5 : Parameter Settings and Functions
5-92
Example:
A rotary motion system uses a motor with a 17-bit encoder. The user
wants to program the system in units of 0.1 degree:
17-bit encoder produces 131072 [counts] per revolution.
360 [degree] = 3600 [0.1 degree]
[ ] [ ]
ator deno ratio units Position
numerator ratio units Position
counts ree
min 3600
131072
deg 1 . 0 1
= =
First option: Second option:
Both options are equivalent.
5.9.1.3. Speed Units
Use the following parameters to convert speed units from [encoder
counts/msec] to [user speed units]:
Parameter Setting
Default
Setting
Signal
Pn2B4 Setting range 1-65535 1 Speed units ratio numerator
Pn2B5 Setting range 0-16383 0
Speed units ratio numerator
(high bits*)
Pn2B6 Setting range 1-65535 1 Speed units ratio denominator
Pn2B7 Setting range 0-16383 0
Speed units ratio denominator
(high bits*)
Speed user units are calculated according to the formula:
1[User speed unit] =
[ ]
[ ]
[ ]
r denominato ratio units Speed
numerator ratio units Speed
ms T
=






counts U
U – number of encoder counts in one speed unit.
T – time of speed units in ms.
The maximum value of numerator (Pn2B4) or denominator (Pn2B6) is
65535. In cases where greater values are required, it is possible to use
parameters Pn2B5 and Pn2B7 for storing the high bits of numerator and
denominator, respectively, according to the following formula:
65535
N
tof Integerpar HB HighBit
= =
65536
• − =
HB N LowBits
, where N- required value.
It is possible to reduce the
fraction so that both the
numerator and denominator are
smaller than 65536:
131072 / 3600 = 32768 / 900
Reduction
Pn2B0 = 32768
Pn2B1 = 0
Pn2B2 = 900
Pn2B3 = 0
Without reduction of the fraction:
High Bits = HB = Integer part of
N/65536 = Integer part of 131072
/ 65536 = 2
Low Bits = N – HB*65536 =
131072 – 2 * 65536 = 0
Pn2B0 = 0
Pn2B1 = 2
Pn2B2 = 3600
Pn2B3 = 0