horsch Leeb 6 GS, Operating Instructions Manual, Page: 94 / 154

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General procedure
1. Determine the required water and prepara-
tion application quantity as per instructions
for use for the crop protection agent.
2. Calculate the filling or refilling quantity for
the area to be treated.
3. Fill half of the solution tank with water.
4. Switch on the agitator.
5. Add the calculated preparation quantity.
6. Top up the remaining amount of water.
7. Before starting spraying stir up the chemical
as instructed by the crop protection product
manufacturer.
8.2.1 Calculating filling and
refilling quantities
Use the "Filling table for residual areas"
(chapter 8.2.2) to calculate the required
refilling quantity for the last solution tank
filling.
Example 1: Filling quantities
The following is known:
Nominal container capacity 1000 l
Residual quantity in container 0 l
Required water 400 l/ha
Preparation requirement per ha
Product A 15 kg
Product B 1.0 l
Question:
How many l of water, how many kg or product
A and how many l of product B do you have to
fill in, if the area to be treated is 2.5 ha?
Calculation formula and solution
Component [quantity/ha] x area [ha]
= required quantity [l or kg]
Water: 400 l/ha x 2.5 ha = 1000 l
Product A: 1.5 kg/ha x 2.5 ha = 3.75 kg
Product B: 1.0 l/ha x 2.5 ha = 2.5 l
Example 2: Preparation addition, area
The following is known:
Nominal container capacity 1000 l
Residual quantity in container 200 l
Required water 500 l/ha
Recommended
concentration 0.15 % l/l or kg/l
Question 1:
How many l or kg preparation must be metered
for one container filling?
Calculation formula and answer to question 1:
Water refill quantity [l] x concentration [% l/l or kg/l]
100
= Addition of preparation [l or kg]
(1000 – 200) [l] x 0.15 [% l/l or kg/l]
100
Question 2:
How big is the area to be treated in ha, which can
be treated with one filling, if the container can
be emptied down to a residual quantity of 20 l?
Calculation formula and answer to question 2:
Available solution [l] – Residual quantity [l]
Required water [l/ha]
= area [ha]
1000 [l] (rated volume) – 20 [l] (residual quantity)
500 [l/ha] required water
= 1.96 [ha]
= 1.2 [l or kg]