Casio FX-CG10, User Manual

Page: 126 / 608

3-10
u To find the minimum value in a list
[OPTN] - [LIST] - [Min]
K
1
(LIST)
6
(
g
)
1
(Min)
6
(
g
)
6
(
g
)
1
(List) <list number 1 - 26>
)
w
Example To find the minimum value in List 1 (36, 16, 58, 46, 56)
A
K
1
(LIST)
6
(
g
)
1
(Min)
6
(
g
)
6
(
g
)
1
(List)
b)
w
u
To find which of two lists contains the greatest value
[OPTN] - [LIST] - [Max]
K
1
(LIST)
6
( g )
2
(Max)
6
( g )
6
( g )
1
(List) <list number 1 - 26>
,
1
(List)
<list number 1 - 26>
)
w
• The two lists must contain the same number of data items. If they don’t, an error occurs.
• The result of this operation is stored in ListAns Memory.
Example To find whether List 1 (75, 16, 98, 46, 56) or List 2 (35, 59, 58, 72, 67)
contains the greatest value
K
1
(LIST)
6
(
g
)
2
(Max)
6
( g )
6
( g )
1
(List)
b,
1
(List)
c)
w
u
To calculate the mean of data items
[OPTN] - [LIST] - [Mean]
K
1
(LIST)
6
( g )
3
(Mean)
6
( g )
6
( g )
1
(List) <list number 1 - 26>
)
w
Example To calculate the mean of data items in List 1 (36, 16, 58, 46, 56)
A
K
1
(LIST)
6
(
g
)
3
(Mean)
6
(
g
)
6
(
g
)
1
(List)
b)
w
u
To calculate the median of data items of specified frequency
[OPTN] - [LIST] - [Med]
This procedure uses two lists: one that contains values and one that indicates the frequency
(number of occurrences) of each value. The frequency of the data in Cell 1 of the first list is
indicated by the value in Cell 1 of the second list, etc.
• The two lists must contain the same number of data items. If they don’t, an error occurs.
K
1
(LIST)
6
(
g
)
4
(Med)
6
(
g
)
6
(
g
)
1
(List) <list number 1 - 26 (data)>
,
1
(List)
<list number 1 - 26 (frequency)>
)
w