Airwell OU-PSINV-25HR, Руководство по установке, Страница: 10 / 76

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Table 1-7 Tubing Data for Models (Single, Twin, Triple, Double-Twin)
Models
Tubing Data
OU-PSINV-25HR OU-PSINV-36HR OU-PSINV-48HR OU-PSINV-60H
Tubing size outer
diameter
Liquid tube mm (in.) 9.52 (3/8) 9.52 (3/8) 9.52 (3/8) 9.52 (3/8)
Gas tube mm (in.) 15.88 (5/8) 15.88 (5/8) 15.88 (5/8) 15.88 (5/8)
Limit of tubing length (m) 50 50 50 50
Limit of elevation
difference between
the 2 units
Outdoor unit is
placed higher
(m)
30 30 30 30
Outdoor unit is
placed lower
(m)
15 15 15 15
Max. allowable tubing length
at shipment
(m)
3 – 30 3 – 30 5 – 30 5 – 30
Required additional refrigerant (g/m) 40 *
2
40 *
2
40 *
2
40 *
2
Refrigerant charged at shipment (kg) 1.9 2.8 3.6 3.6
No additional charge of compressor oil is necessary.
*
1 If total tubing length becomes 30 to 40 m, charge additional refrigerant by 20 g/m.
*
2
If total tubing length becomes 30 to 50 m, charge additional refrigerant by 40 g/m.
Table 1-8 Connection Tube Sizes
Main tubing (L)
Double-Twin distribution tube (L1, L2)
Indoor unit connection tube
( 1, 2, 3, 4)
Total type capacity of indoor unit connected after
the branch
Type capacity of indoor unit 25 – 60 25 25 – 60 12 – 18
Gas tube ø15.88 ø15.88 ø15.88 ø12.7
Liquid tube ø9.52 ø9.52 ø9.52 ø6.35
Amount of additional charge per 1 m 40 g 40 g 40 g 20 g
Charge with the amount of additional refrigerant calculated using the formula below, based on the values in Table 1-8 and the size and
length of the liquid tubing.
Amount of additional refrigerant charge (g)
Do not remove refrigerant from the system, even if the result of the calculation is negative.
Additional refrigerant amount (g) = Additional refrigerant for main tubing (g) + Additional refrigerant for distribution tubing (g)
– Outdoor unit charge-less refrigerant amount (g)
= 40X (a) + 40X (b) + 20X (c) – 1200 (25 – 60 type)
(Use with the current refrigerant charge.)
(a) Actual length (m) of main tubing (ø9.52)
Refrigerant charge per 1 m of actual length = 40 g/m (25 – 60 type)
(b) Total length of distribution tubing (ø9.52) Refrigerant charge per 1 m of actual length = 40 g/m
(c) Total length of distribution tubing (ø6.35) Refrigerant charge per 1 m of actual length = 20 g/m
Example
●
Sample tubing lengths
L = 35 m 1 = 5 m
L1 = 10 m 2 = 5 m
L2 = 5 m 3 = 5 m
4 = 10 m
●
Find the liquid tube size from Table 1-8.
L : ø9.52 (48 type)
L1 : ø9.52 (Total type capacity of indoor unit 24)
L2 : ø9.52 (Total type capacity of indoor unit 24)
1 – 4 : ø6.35
●
The amount of additional on-site refrigerant charge is found by
subtracting the outdoor unit charge-less refrigerant amount from the
total charge amount for all tube sizes.
ø9.52
→
L : 35 m
×
40 g / m = 1400
ø9.52
→
L1 + L2 : (10 + 5) m
×
40 g / m = 600
ø6.35
→
1 – 4 : (5 + 5 + 5 + 10) m
×
20 g / m = 500
Outdoor unit charge-less refrigerant amount –1200
Total +1300
●
The amount of additional on-site refrigerant charge is 1,300 g.
Note: For type 18, the additional refrigerant charge for tubing length (d)
of 30 to 40 m is the following:
Additional refrigerant amount (g) = 20X (d) – 600
L
L1
L2
4
3
2 1
Outdoor unit
Indoor unit (12 type × 4)
Airwell̲PAC-i̲eng.indb 10 Airwell̲PAC-i̲eng.indb 10 2009/07/09 16:13:18 2009/07/09 16:13:18