APPENDICES
APP
−
70
A
P
=
A
P
A
L
A
M
=
16384(PLS)
360.00000(degree) 3/11
=
16384(PLS) 11
360.00000(degree) 3
=
180224
1080.00000
S
∆
Here, reduce the above result since the A
P
setting must be made not more than
65535.
A
P
A
L
A
M
=
11264
67.50000
Next, since the A
L
setting range is up to 0.65535, set 0.06750 as A
L
and multiply it
by 1000 with A
M
.
A
P
=
11264(A
P
)
0.06750(A
L
) 1000(A
M
)
A
L
A
M
Thus, A
P
, A
L
and A
M
to be set are as follows.
A
P
=11264
A
L
=0.06750
A
M
=1000
(4) When mm is set as the control unit for conveyor drive (calculation including
π
)
When the belt conveyor drive is used, the conveyor diameter is 135mm, the
pulley ratio is 1/3, the motor is HC-SF (16384PLS/rev) and the reduction ratio of
the reduction gear is 7/53
Motor
Reduction
gear 7/53
Pulley
ratio 1/3
135mm
Belt conveyor
As the travel value of the conveyor is used to exercise control, set mm as the
control unit.
First, find how many millimeters the load (machine) will travel (
∆
S) when the
motor turns one revolution (A
P
).
A
P
(number of pulses per motor revolution)
= 16384 (PLS)
∆
S (machine travel value per motor revolution) = 135000.0(
µ
m)
×π×
reduction
ratio
= 135000.0(
µ
m)
×π×
7/53
×
1/3
Substitute this for the above relational expression.
At this time, make calculation with the reduction ratio 7/53
×
1/3 remaining as a
fraction.
A
P
=
A
P
=
16384(PLS)
=
S
A
L
A
M
135000.0( m) 7/53 1/3
135000.0( m) 7
16384(PLS) 53 3
∆
Here, make calculation on the assumption that
π
is equal to 3.14159.
A
P
=
A
P
A
L
A
M
=
2605056
2968802.6
S
∆
