Examples and tips
PROGRAMMING MANUAL
248
Revi
si
on 3.0
One solution is:
Because the greatest common divisor of Pn202 and Pn203 must
be 1, we get: Pn202 = 17 and Pn203 = 500. Therefore, the
parameters are:
To calculate the multiturn limit setting Pn205, we have:
The evident solution is:
n
= 100 and
m
= 1224. Or, when we simplify
the factors:
n
= 25 and
m
= 306. Therefore: Pn205 = m – 1 = 305.
With these settings, executing
MOVE(180)
moves the moving part
180 tenths of an angle degree or 18 angle degrees in forward
direction.
UNITS = 2 = 131072
Pn202 = 1224
Pn203 = 360000
17
UNITS = 131072
Pn202 = 17
Pn203 = 500
Pn205 = 16
REP_DIST = 3600
REP_OPTION = 1
m motor_revolution = n machine_cycle = n 12.24 motor_revolution
.
.
.
.
I52E-EN-03.book Seite 248 Freitag, 29. Juni 2007 11:55 11