MIL'S PRO2XY, Инструкции по запуску и обслуживанию, Страница: 15 / 48

PRO
2
XY OXYGEN CONCENTRATOR
519211-22 13
EN
CHOICE OF ROOM
The concentrator must be located in a clean, non-humid, non-saline, dustless and ventilated room.
the temperature in the room should be b5C and +40C.
Forced ventilation controlled by a thermostat must be installed to ensure adequate room ventilation.
6.1 Compressor room ventilation
* Concerning the ventilation of the room, we recommend a renewal of 6 times the volume of the room per hour.
This
𝑸
𝒂
flow rate should be extracted mechanically.
𝑸
𝒂
= 𝑺 × 𝒉 × 𝟔
with
𝑸
𝒂
= Exhaust air flow rate (m³/h)
S
= Floor area of the room (m²)
h = Room height (m)
* If the cooling air discharge from the compressors is not channeled, this air flow to be extracted must be added according to the
formula:
𝑸
𝐛
=
𝑷 × 𝟏𝟎𝟎𝟎 × 𝟑𝟔𝟎𝟎
∆𝑻° × 𝑪𝒑 × 𝝆 = 𝟑𝟎𝟐𝟒 ×
𝑷
∆𝑻°
with
𝑸
𝒃
= Flow of air to be extracted (m³/h)
P
= Thermal power to be discharged (kW)
–
see table below.
ΔT
° = Temperature difference between the air in the premises and the outside air (10K maximum recommended)
Cp
= Specific heat of the air = 1005 J.kg -1 .K -1 at 25°C

= Density of the air = 1.1845 kg.m
-3
at 25°C
Type of
compressor
Thermal power to be
discharged by compressor
(kW)
Heat generation
(kCal/h)
MVX 2 2.2 1 892
MVX 3 3 2 580
MVX 4 4 3 440
MVX 5
5.5 4 730
MVA 9 7.5 6 450
MVB 12 11 8 340
MVB 16 15 10 576
MVC 19 18.5 18 920
MVC 23 22 18 920
MVD 31 30 25 800
MVE 38
37 31 820
MVE 46 45 38 700
MVF 55 55 47 330
Example
: For two MVB12 compressors, with no sheathing of the cooling air discharge, in a 30 m² area with h=2.7 meters.
𝑸
𝒂
: Renewal of the air of the premises 6 times per hour gives:
𝑸
𝒂
= 𝟑𝟎 × 𝟐. 𝟕 × 𝟔 = 𝟒𝟖𝟔 𝒎³/𝒉
𝑸
𝒃
: Then, thermal power to be discharged:
𝑷 = 𝟐 × 𝟏𝟏 𝒌𝑾 = 𝟐𝟐 𝒌𝑾
With allowable ΔT
= 10°C
𝑸
𝒃
= 𝟑𝟎𝟐𝟒 ×
𝟐𝟐
𝟏𝟎 = 𝟔𝟔𝟓𝟐 𝒎³/𝒉
The sum of the 2 flow is: 6652 + 486 = 7138 m³/h.
The ventilation must be at least
7138 m³/h
.