I-2
(7 + 9) x 3 = 48
5. Add the results of steps 3 and 4:
9 + 48 = 57
6. Subtract the result of step 5 from the next highest multiple of 10:
60 - 57 = 3
7. The checksum becomes the low-order digit:
19873
8. Because the data now has an odd length, a leading zero is added,
for the final result of
019873