32
Diameter of liquid pipe
mm(in.)
28.6(1-1/8) 25.4(1)
22.2(7/8) 19.05(3/4) 15.9(5/8) 12.7(1/2) 9.52(3/8) 6.35(1/4)
kg/m
0.680
0.520
0.350
0.250
0.170
0.110
0.054
0.022
OZ/in.
0.61
0.47
0.31
0.22
0.15
0.10
0.05
0.02
(2) ∑Refrigerant charging amount B of every module
Refrigerant charging amount
B of every module
kg(Pounds)
②
Module capacity(kW)
IDU/ODU rated
capacity
collocation ratio C
①
Quantity
of
included
IDUs
22.4
28.0
33.5
40.0
45.0
50.4
56.0
61.5
50%≤C≤70%
<
4
0
0
0
0
0
0
0
0
≥
4
0.5(1.1) 0.5(1.1) 0.5(1.1) 0.5(1.1) 0.5(1.1) 0.5(1.1) 1(2.2) 1.5(3.3)
70%
<
C≤90%
<
4
0.5(1.1) 0.5(1.1)
1(2.2)
1.5(3.3) 1.5(3.3) 1.5(3.3) 2(4.4)
2(4.4)
≥
4
1(2.2)
1(2.2)
1.5(3.3)
2(4.4) 2(4.4) 2.5(5.5) 3(6.6) 3.5(7.7)
90%
<
C≤105%
<
4
1(2.2)
1(2.2)
1.5(3.3)
2(4.4) 2(4.4) 2.5(5.5) 3(6.6) 3.5(7.7)
≥
4
2(4.4)
2(4.4)
3(6.6)
3.5(7.7) 3.5(7.7) 4(8.8) 4.5(9.9) 5(11.0)
105%
<
C≤135%
<
4
2(4.4)
2(4.4)
2.5(5.5)
3(6.6) 3(6.6) 3.5(7.7) 4(8.8)
4(8.8)
≥
4
3.5(7.7) 3.5(7.7)
4(8.8)
5(11.0) 5(11.0) 5.5(12.1) 6(13.2) 6(13.2)
①
IDU/ODU rated capacity collocation ratio C = Sum of rated cooling capacity of indoor
unit / Sum of rated cooling capacity of outdoor unit
②
If all of the indoor units are fresh air indoor units, the quantity of refrigerant added to
each module is 0kg.
③
If outdoor air processor is connected with normal VRF indoor unit, adopt the perfusion
method for normal indoor unit for perfusion.
For example1:
Outdoor unit consists of one 28kW
(96000 Btu/h)
module and one 45kW
(150000 Btu/h)
module. Five 14kW
(48000 Btu/h)
duct type units are used as indoor units.
IDU/ODU rated capacity collocation ratio C= 140×5/(280+450)=96%. The quantity of
included IDUs is more than 4 sets. Please refer to the above table.
Additional refrigerant quantity B for 28kW module is 2.0kg(4.4lbs).
Additional refrigerant quantity B for 45kw module is 3.5kg(7.7lbs).
So, ∑Refrigerant charging amount B of every module=2.0+3.5=5.5kg(12.1lbs)
Suppose the Pipeline charging amount A=∑Liquid pipe length×refrigerant charging
amount of every 1m liquid pipe=20kg(44.1lbs)
Total refrigerant charging amount R=20+5.5=25.5kg(56.2lbs)
For example 2:
Outdoor unit is a 45kW module and the indoor unit is a 45kW fresh air unit. The quantity (B)
of refrigerant added to this module is 0kg.
So,
∑
B (Quantity of refrigerant added to each module) = 0kg
Lennox
VRF Unit