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Technical data
86
Fuses
gG and aR fuses for protection against short-circuit in the input power cable or drive
are listed below. Either fuse type may be used if it operates rapidly enough. Choose
between gG and aR fuses according to the table under
on page
or verify the operating time by
checking that
the short-circuit current of the installation is at least the value given in the fuse
table
. The short-circuit current can be calculated as follows:
where
I
k2-ph
= short-circuit current in symmetrical two-phase short-circuit (A)
U
= network line-to-line voltage (V)
R
c
= cable resistance (ohm)
Z
k
= z
k
·
U
N
2
/
S
N
= transformer impedance (ohm)
z
k
= transformer impedance (%)
U
N
= transformer rated voltage (V)
S
N
= nominal apparent power of the transformer (kVA)
X
c
= cable reactance (ohm).
Calculation example
Drive:
•
ACS800-04-0260-3
•
supply voltage
U
= 410 V
Transformer:
•
rated power
S
N
= 3000 kVA
•
rated voltage
U
N
= 430 V
•
transformer impedance z
k
= 7.2%.
Supply cable:
•
length = 170 m
•
resistance/length = 0.112 ohm/km
•
reactance/length = 0.0273 ohm/km.
I
k2-ph
=
2
·
R
c
2
+ (
Z
k
+
X
c
)
2
U
·
(430 V)
2
3000 kVA
= 4.438 mohm
Z
k
= z
k
·
U
N
2
S
N
= 0.072
Summary of Contents for ACS800-04
Page 4: ......
Page 12: ...Safety instructions 12 ...
Page 54: ...Planning the electrical installation 54 ...
Page 72: ...Motor control and I O board RMIO 72 ...
Page 116: ...Resistor braking 116 ...
Page 117: ......