Martin Imager Series, Руководство оператора

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36 Synchronous triggering during Stand-Alone operation
6 If a slave has more scenes than the master calls, the last scenes in the
slave will never be executed, as is the case with scene S4 in the following
example.
7 A slave fixture will not listen for the next message from the master fixture
before it has finished its current scene. This may result in a slave skipping a
scene if slave has a longer scene time than master. Note that in the
following example the scenes in the Slave run out of their programmed
sequence because scenes 0 and 2 on the Slave are longer than the
corresponding scenes on the Master.
F=fade, W=wait Timeline =>
M0
M1 M2 M3
Programmed in Master F W F W F W F W
S0 S1 S2 S3 S4
Programmed in Slave F W F W F W F W F W
Result M0 M1 M2 M3
F W F W F W F W
S0 S1 S2 S3
F W F W F W -- -- F W
M=master, S=slave
F=fade, W=wait
Time >
Programmed M0 M1 M2
Master F W F W F W
S0 S1 S2
Slave F W F W F W
Result M0 M1 M2 M0 M1
Master F W F W F W F W F W
S0 S2 S1
Slave F W F W .. .. F W .. ..