Continental Fireplaces CB30NTR, Инструкция по установке и эксплуатации

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21
EN
W415-1398 / C / 06.15.17
H
2
= 1 FT (0.3m)
H
3
= 1 FT (0.3m)
H
4
= 1.5 FT (0.5m)
H
R
= H
1
+ H
2
+ H
3
+ H
4
= 2FT (0.6m) + 1FT (0.3m) + 1FT (0.3m) + 1.5FT (0.5m) = 5.5 FT (1.7m)
H
O
= .03 (four 90° elbows - 90°) = .03 (360° - 90°) = 8.1 FT (2.5m)
H
T
= H
R
+ H
O
= 5.5 FT (1.7m) + 8.1 FT (2.5m) = 13.6 FT (4.2m)
H
T
+ V
T
= 13.6 FT (4.2m) + 5.5 FT (1.7m) = 19.1 FT (5.8m)
Formula 1: H
T
< 4.2 V
T
4.2 V
T
=4.2 FT (1.3m) x 5.5 FT (1.7m) = 23.1 FT (7m)
13.6 FT (4.2m) < 23.1 FT (7m)
Formula 2: H
T
+ V
T
< 24.75 FT (7.5m)
19.1 FT (5.8m) < 24.75 FT (7.5m)
Since both formulas are met, this vent configuration is acceptable.
16.16
3.9 REAR EXIT HORIZONTAL TERMINATION
(H
T
) < (V
T
)
Simple venting configuration See graph to determine the required vertical rise V
T
for the required
(only two 90° elbows) horizontal run H
T
.
For vent configurations requiring more than two 90° elbows, the following formulas apply:
Formula 1: H
T
< V
T
90°
F
o
r
m
u
l
a
2
:
H
T
+
0
2.5
(0.8)
5
(1.5)
7.5
(2.3)
10
(3.1)
12.5
(3.8)
15
(4.6)
40 (12.2)
10 (3.1)
20 (6.1)
30 (9.1)
17.5
(5.3)
20
(6.1)
1.6
(0.5)
1.6 (0.5)
38.3 (11.7)
REQUIRED
VERTICAL
RISE IN
FEET
( METERS) V
T
HORIZONTAL VENT RUN PLUS OFFSET IN FEET (METERS) H
T
The shaded area within the lines represents acceptable values for H
T
and H
T