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I.L. 40-385.1B
6-2
(5/92)
• Phase current (
∆
I
A
,
∆
I
B
, or
∆
I
C
) >1.0A peak and
12.5% change
• Ground current (
∆
I
0
)>0.5 A peak
• Voltage (
∆
Van,
∆
Vbn, or
∆
Vcn ) >7V and 12.5%
change with a current change of
∆
I>0.5 A
When one of the above is true, MDAR starts fault pro-
cessing. In order to perform the above, apply a certain
value of current
suddenly. If MDAR does not trip, turn
the current off, readjust to a higher value, and then
suddenly reapply current.
The current required to trip can be calculated using the
following:
From Table 6-1:
• Z1G
= 4.5
Ω
• PANG
= 75
°
• ZR
= 3.0
using an X = 75
° (
lagging)
The current required to trip = 4.00A
±
5 % for fault cur-
rent lagging fault voltage by 75
°
. This is the maximum
torque angle test. For other points on the MHO circle,
change X to a value between 0
°
and 150
°
, and calcu-
late the value of I.
See Table 4-3, for a description of the following dis-
played fault data for:
• Fault Type (FTYP)
• Targets (BK1, Z1G)
• Fault Voltages (V
A
, V
B
, V
C
, 3V
0
) and Currents
(I
A
, I
B
, I
C
, 3I
0
)
With the external jumper connected between TB1-13
and TB1-14, the BFIA-1, BFIA-2 should be closed. The
GS contact will be ON for approximately 50 ms. when
the fault is applied. Alarm 2 relay will be picked-up,
which can be reset by the RESET button after the fault
is removed. Change TTYP to 1PR; the RI2-1 and RI2-
2 should be CLOSED. Change TTYP to 2PR (or 3PR).
Repeat test; RI2-1 and RI2-2 should be closed.
Change TTYP to “OFF”. Repeat test. RI2-1, RI2-2
should not be picked-up.
Repeat AG fault and measure the trip time, which
should be < 2 cycles. Change the setting of T1 from No
I
V
LN
Z
1G
COS PANG
X
–
(
)
1
Z
R
1
–
(
)
3
---------------------
+
-------------------------------------------------------------------------------------------
=
to Yes. Repeat the test; the trip time should extend
for an additional 2 cycles. Reset T1 to zero.
The following formula can be used when PANG
≠
GANG:
Vxg = (I
X
+ K
0
I
0
) Zcg
or
Vxg =
Zcg
or
I
X
=
where
K
0
=
=
I
X
=
or
I
X
=
Example:
Vag = 30
Z1g = 4.5
PANG = 85
GANG = 40
Zr = 3
Ia
=
=
=
This is the trip current (4.3A) at the maximum torque
angle of -57.7
6°
(current lags voltage by 57.76
°
).
The following equation should be used for the angle
of x on the MHO circle:
Iax
=
Step 11. Using Figure 6-1, Configurations 2 and 3,
repeat (preceding) Step 10 for BG and CG faults.
Note Targets.
I
x
K
0
I
x
3
------------
+
V
xg
Z
cg
1
K
o
3
-------
+
-------------------------------
Z
oL
Z
1L
–
(
)
Z
1L
------------------------------
Z
R
GANG
PANG
–
(
)
-1
∠
V
xg
Z
cg
e
jPANG
1
Zr e
j GANG
PANG
–
(
)
1
–
3
----------------------------------------------------------------
+
----------------------------------------------------------------------------------------------------------------
V
xg
2
3
---
Z
cg
e
jPANG
1
3
---
Z
cg
Z r
e
jGANG
+
----------------------------------------------------------------------------------------------
30
2
3
---
4.5
(
)
e
j85
1
3
---
4.5
(
)
3
( )
e
j40
+
---------------------------------------------------------------------
30
3
85
( )
+ j 3 sin (85) + 4.5 cos (40) + j4.5 sin (40)
cos
------------------------------------------------------------------------------------------------------------------------------
4.31
57.76
–
(
)
∠
30
6.96
57.76
x
–
(
)
cos
------------------------------------------------
Содержание REL-300
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Страница 116: ...I L 40 385 1B 6 14 5 92 Figure 6 1 Test Connection for Single Phase to Ground Faults Sheet 1 of 4...
Страница 117: ...I L 40 385 1B 5 92 6 15 Figure 6 2 Test Connection for Three Phase Faults 1502B51 Sub 1 Sheet 2 of 4...
Страница 118: ...I L 40 385 1B 6 16 5 92 Figure 6 3 Test Connection for Phase to Phase Faults 1502B51 Sub 1 Sheet 3 of 4...
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Страница 135: ...I L 40 385 1B SD 6 5 92 Figure SD 2 MDAR Block Diagram sheet 1 of 1 Sub 1 1611C12...