Siemens 1FW6092-2PC15-6AB3, Руководство по настройке

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Configuration
5.3 Examples
1FW6 High Speed built-in torque motors
Configuration Manual, 01/2020, 6SN1197-0AE03-0BP3
107
The following applies for the required acceleration torque:
M
a
= (J + J
m
) • α
Since the moment of inertia J
m
for the 1FW6 motor is not known at the time of configuring,
then initially J
m
= 0 kgm
2
must be assumed.
M
a
= 5.1 kgm
2
• 52.36 rad/s
2
= 267 Nm
To accelerate the specified mass, a torque M
a
of 267 Nm is required.
M
m
= M
r
+ M
a
M
m
= 60 Nm + 267 Nm = 327 Nm
Together with the constant frictional torque M
r
, a motor torque of M
m
= 327 Nm. is obtained.
Select a suitable motor for this from the table "Built-in torque motors: overview" according to
the following criteria:
● Maximum torque at least 327 Nm.
● Maximum speed at least 100 rpm, specifying the max. torque
For positioning, you will already find 4 suitable motors in the series with the smallest shaft
height in Table "Built-in torque motors: overview" in Chapter "Selection and ordering data
1FW6 High Speed (Page 46)":
1FW6092-xxC05-2Exx: not suitable (maximum torque 214 Nm too low)
1FW6092-xxC05-4Fxx: not suitable (maximum torque 214 Nm too low)
1FW6092-xxC10-4Fxx: suitable (maximum torque 429 Nm high enough)
1FW6092-xxC10-8Fxx: suitable (maximum torque 429 Nm high enough)
1FW6092-xxC15-6Axx: suitable (maximum torque 643 Nm high enough)
1FW6092-xxC15-8Fxx: suitable (maximum torque 643 Nm high enough)
The moment of inertia of the motor 1FW6092-xxC10-4Fxx is J = 0.0689 kgm
2
.
The accelerating torque M
a
can now be corrected to:
M
a
= (5.1 kgm
2
+ 0.0689 kgm
2
) • 52.36 rad/s
2
= 271 Nm
This means that the total motor torque required increases M
m
= M
r
+ M
a
up to 330 Nm.
The requirement from the "Positioning" machining type is 330 Nm.